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Nookie1986
7 days ago
13

Lourdes plans to jog at least 1.5 miles. Lourdes averages 3.75 mph pace when she jogs write and solve an inequality to find x, t

he number of hours lourdes will have to jog
Mathematics
1 answer:
lawyer [4K]7 days ago
4 0

Answer:

Step-by-step explanation:

"At least" indicates a minimum requirement, hence we will utilize this notation. Our aim is to formulate an inequality that connects the distance Lourdes plans to jog with her jogging time multiplied by speed, as time multiplied by speed equates to distance.

We formulate the inequality as 1.5 ≤ 3.75x.

This indicates that 1.5 will consistently be less than or equal to the distance she jogs. Please ask if you need clarification. Following this, proceed to solve for x.

You might be interested in
out of fifty students,34 joined the journalism class and 25 joined robotics club.if 16 students joined both clubs,how many stude
AnnZ [3900]

Answer:

Step-by-step explanation:

Overall students=50

35 -> j.

25 -> r.

16-> j.+r.

35-16=19 students joined j.

25-16=9 joined r.

50-19+9

50-28=22

The answer is 22

It would be nice if you could give me the brainliest rating. Best of luck!

3 0
2 days ago
Ariel has a plastic ice cream cone in her food playset. The ice cream cone is a half-sphere sitting on top of a cone. What is th
tester [3938]
I believe the volume is approximately 1742.54 cm³.
5 0
4 days ago
Read 2 more answers
Jai Narayan sells two radio sets for 2288 each.
tester [3938]

Answer:

1%

Step-by-step explanation:

The selling price for each radio is $2288.

Total selling price is 2\times 2288=$4576.

Profit is 10%.

Loss is also 10%.

Cost price=\frac{S.P\times 100}{100+gain(in\;percent)}

Cost price=\frac{S.P\times 100}{100-loss(in\;percent)}

Utilizing the formula,

Cost price of the first radio is \frac{2288\times 100}{110}=$2080.

Cost price of the second radio is \frac{2288\times 100}{100-10}=$2542.2.

The combined cost price for both radios totals 2080+2542.2=$4622.2.

Total cost price exceeds total selling price.

Loss equals selling price minus cost price.

Loss is calculated as 4622.2-4576=$46.2.

Loss%=\frac{Loss}{C.P}\times 100

Loss percentage is \frac{46.2}{4622.2}\times 100=1%.

Thus, the loss is 1%.

5 0
3 days ago
a resorvoir can be filled by an inlet pipe in 24 hours and emptied by an outlet pipe 28 hours. the foreman starts to fill the re
zzz [4035]
To determine the rates at which the inlet and outlet pipes fill and empty the reservoir, we remember that work done equals rate multiplied by time. Let’s denote the inlet rate as i and for the outlet pipe as 0. Therefore,
i(24) = 1
o(28) = 1
In this context, the '1' represents the total number of reservoirs, since the problem states the time needed for each pipe to either fill or empty a singular reservoir. Solving for rates yields:
i = 1/24 reservoirs/hour
o = 1/28 reservoirs/hour

Over the first six hours, the inlet pipe fills (1/24)(6) = 1/4 reservoirs and during the same period, the outlet pipe empties (1/28)(6) = 3/14 reservoirs. To calculate the net volume of the reservoir filled, we subtract the emptying total from the filling total:
1/4 - 3/14 = 1/28 reservoirs (note that if emptying exceeds filling, a negative value results. In such cases, treat that negative value as zero, indicating that the outlet rate surpasses the inlet rate, leading to an empty reservoir).
Now we need to find out how long it will take to fill up one reservoir since we’ve already partially filled 1/28 of it, after closing the outlet pipe. In simpler terms, we need to determine the time required for the inlet pipe to finish filling the remaining 27/28 of the reservoir. Fortunately, we have already established the filling rate for the inlet pipe, leading to the equation:
(1/24)t = 27/28
Solving for t gives us 23.14 hours. Remember to add the initial 6 hours to this result since the question seeks the total time. Thus, the final total is 29.14 hours.

Please ask me any questions you may have!
4 0
7 days ago
Read 2 more answers
The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [3949]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

7 0
12 days ago
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