The string does not experience any force of tension, as it balances two forces acting in the same direction. Hence, the tension is zero.
Explanation:
If tension existed in the string, it would mean that two equal but opposite forces are exerting pull in contrary directions.
When a force of f newtons is applied from the right and another force of f newtons from the left, the resulting action occurs through one force. Because there is action on the same string in opposing directions, the tension in the string can only be equal to the magnitude of the string itself.
Therefore, the string indeed has no tension since it is dealing with two forces acting in the same direction. Thus, the tension is zero.
The ratio is defined as

. Explanation: The problem indicates that
is the first radius while

is the second radius. The angular velocity of the turntable can be mathematically denoted as , and for the rubber roller it is represented as . In both cases,

represents the speed of both the turntable and rubber roller.
Answer:
The number of photons emitted each second is
Explanation:
Let 'n' stand for the quantity of photons released by the bulb.
Provided Information:
The bulb radiates energy at a rate of 100 J per second (E).
Wavelength of emitted light is (λ) = 525 nm = 
The energy of a photon is calculated by:
Where,

Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,

To express in terms of 'n', we find:

Insert the provided values and solve for 'n'. The resulting calculation yields

Consequently,
photons are discharged every second.
The frequency is calculated to be 735 Hz. Given:
Person's distances to speakers are r₁ = 4.1 m and r₂ = 4.8 m. The path difference calculates to d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m. In terms of destructive interference, we derive: λ = v/f, where v is the sound speed of 343 m/s. Using n = 1 gives f = 245 Hz, and for n = 3, f = 735 Hz. Thus, the second lowest frequency for destructive interference is 735 Hz.