answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Cloud
7 days ago
8

A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a 1.19 meter high desk. How far awa

y does the book land?
Physics
1 answer:
Yuliya22 [1.1K]7 days ago
8 0

Answer:

2.45 m

Explanation:

To begin, we need to determine the book's time of flight, utilizing the equation for vertical motion:

h=\frac{1}{2}gt^2

with

h = 1.19 m representing the height traveled by the book

g = 9.8 m/s^2 being the gravitational acceleration

t symbolizing the time of flight

By solving for t,

t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(1.19)}{9.8}}=0.49 s

Next, we calculate the horizontal distance the book travels, defined by

d=v_x t

where

v_x = 5.0 m/s denotes the horizontal velocity

t = 0.49 s being the time of flight

By substituting,

d=(5.0)(0.49)=2.45 m

Thus, the book lands at a distance of 2.45 m.

You might be interested in
Write a hypothesis about the effect of increasing voltage on the current in the circuit. Use the "if . . . then . . . because .
Yuliya22 [1153]

Hypothesis: An increase in voltage should result in a corresponding rise in current because according to Ohm's Law,

I \propto V

I=\frac{V}{R}

Ohm's Law indicates that current is proportional to voltage when resistance remains constant. Hence, if resistance stays the same, elevating the voltage will lead to an increase in current. Conversely, if voltage remains unchanged and resistance increases, current will decrease.

3 0
3 days ago
Read 2 more answers
Consider the uniform electric field \vec{E} =(4000~\hat{j}+3000~\hat{k})~\text{N/C} ​E ​⃗ ​​ =(4000 ​j ​^ ​​ +3000 ​k ​^ ​​ ) N/
kicyunya [1025]

Answer:

Electric flux is calculated as \phi=31562.63\ Nm^2/C

Explanation:

We start with the given parameters:

The electric field impacting the circular surface is E=(4000j+3000k)\ N/C

Our objective is to ascertain the electric flux passing through a circular region with a radius of 1.83 m situated in the xy-plane. The area vector is oriented in the z direction. The formula for electric flux is expressed as:

\phi=E{\cdot}A

\phi=(4000j+3000k){\cdot}Ak

Applying properties of the dot product, we calculate the electric flux as:

\phi=3000\times Ak

\phi=3000\times \pi (1.83)^2

\phi=31562.63\ Nm^2/C

Consequently, the electric flux for the circular area is \phi=31562.63\ Nm^2/C. Thus, this represents the required answer.

4 0
1 day ago
A 25kg child sits on one end of a 2m see saw. How far from the pivot point should a rock of 50kg be placed on the other side of
Sav [1105]

Answer:

A rock weighing 50kg should be positioned at a distance of 0.5m from the pivot of the seesaw.

Explanation:

τchild=τrock  

We will utilize the formula for torque:

(F)child(d)child)=(F)rock(d)rock)

The gravitational force acts equally on both objects.

(m)childg(d)child)=(m)rockg(d)rock)

We can eliminate gravity from both sides of the equation for simplification.

 (m)child(d)child)=(m)rock(d)rock)  

Now employing the given masses for the rock and child. The seesaw's total length is 2 meters, with the child sitting at one end, placing them 1 meter from the center of the seesaw.

(25kg)(1m)=(50kg)drock

Solve for the distance where the rock should be positioned in relation to the seesaw's center.

drock=25kg⋅m50kg

drock=0.5m

6 0
5 days ago
Which statements about inertia and centripetal force are correct? Check all that apply. Inertia is always present. Inertia cause
kicyunya [1025]
Inertia is universally present. It's important to note that inertia doesn't serve as the force keeping objects in circular paths; that role belongs to centripetal force, which is not always present. Centripetal force actively pulls objects towards the center of a circle. Both inertia and centripetal force contribute to the phenomenon of circular motion. Thank you, and enjoy your day;)
6 0
5 days ago
Read 2 more answers
a force of 6lbs acts on an object with a weight of 35 lbs on earth. determine the objects acceleration. final answer must be 5.5
kicyunya [1025]
Weight of the object = 35 lbs
F = ma
m = F/a = 35/32 (with acceleration of 32 ft/s²)
m= 1.09

Again applying the same formula,
a = F/m
a= 6/1.09
a= 5.489

Thus, the acceleration is approximately 5.5 ft/s²!!
5 0
3 days ago
Read 2 more answers
Other questions:
  • 4 A wheel starts from rest and has an angular acceleration of 4.0 rad/s2. When it has made 10 rev determine its angular velocity
    13·1 answer
  • The summer camps had a field trip from the campus to the fragrance Hill they traveled at an average speed of 65 km an hour and t
    6·1 answer
  • Each plate of a parallel-plate capacator is a square with side length r, and the plates are separated by a distance d. The capac
    13·1 answer
  • A cylindrical tank of methanol has a mass of 40 kgand a volume of 51 L. Determine the methanol’s weight, density,and specific gr
    10·1 answer
  • An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0 km/hour is blowing southward.
    15·1 answer
  • An electron is trapped in a square well of unknown width, L. It starts in unknown energy level, n. When it falls to level n-1 it
    15·1 answer
  • The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca
    7·1 answer
  • A locomotive is accelerating at 1.6 m/s2. it passes through a 20.0-m-wide crossing in a time of 2.4 s. after the locomotive leav
    13·2 answers
  • A quantum system has three energy levels, so three wavelengths appear in its emission spectrum. the shortest observed wavelength
    7·1 answer
  • What is another metaphor (aside from the fact that a piano can only produce certain notes) that could help someone understand en
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!