Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.

Question

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Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.

The distance d between both lines is 4.10 m. What is the magnitude of the electric field at a point equidistant from the lines, with a distance 2d from both lines?

Physics

1 answer:

Sav [3.1K] · Answer 1 · 2026-03-09T08:47:47+03:00

Answer:

The strength of the electric field at an equidistant point from the lines is $4.08\times10^{5}\ N/C$

Explanation:

Given that,

Positive charge = 24.00 μC/m

Distance = 4.10 m

We need to find the angle

Using angle formula

$\theta=\sin^{-1}(\dfrac{\dfrac{d}{2}}{2d})$

$\theta=\sin^{-1}(\dfrac{1}{4})$

$\theta=14.47^{\circ}$

We need to determine the magnitude of the electric field at a point equidistant from the lines

Using electric field formula

$E=\dfrac{2k\lambda}{r}\times2\cos\theat$

Plugging the values into the formula

$E=\dfrac{2\times9\times10^{9}\times24.00\times2\times10^{-6}\cos14.47}{2.05}$

$E=408094.00\ N/C$

$E=4.08\times10^{5}\ N/C$

Thus, the magnitude of the electric field at a point equidistant from the lines is $4.08\times10^{5}\ N/C$