Write one to two sentences explaining whether this passage from the story is exposition, rising action, climax, or resolution: “
2 answers:
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Answer:
The books are displaced to the left due to inertia and ultimately halt when impacted by the car door.
Explanation:
The movement of the books can be understood through Newton's first two laws:
- The first law (Law of Inertia): an object will remain at rest or continue moving in a straight line unless an unbalanced force acts upon it.
- The second law: if unbalanced forces act on an object, it experiences an acceleration that can be described by the formula
where F is the object's net force, m its mass, and a its acceleration.
Now let's relate this to the scenario:
- When Argelia makes a sharp right turn, the books, which are not secured in the car, maintain their straight-line motion due to inertia so they appear to move left as the car shifts right.
- Upon contacting the car door, the books cease moving due to the second law: the door exerts an unbalanced force, causing the books to decelerate and ultimately come to rest.
Answer:
(1) En to n-1 = 0.55 eV
(2) En-1 to n-2 = 0.389 eV
(3) ninit =4
(4) L =483.676 ×10^-11 nm
(5) λlongest= 1773.33 nm
Explanation:
The comprehensive details regarding the answer are provided in the attached files.
Answer:
Explanation:
Within a duration of 60 seconds, six waves are observed.
With a total of 6 waves,
this equates to 3 wavelengths.
As a result,
the period for each wavelength is calculated as 60 divided by 3.
Thus, period = 20 seconds.
According to the frequency-period relationship,
f = 1 / T
f = 1 / 20
f = 0.05 Hz
Response:
Clarification:
Refer to the diagram indicating the charges on the specified sphere (see attachment).
The electric field at the stated positions is
E(r) = 0 for r≤a. Equation 1
E(r) = kq/r² for a<r<b. Equation 2
E(r) = 0 for b<r<c. Equation 3
E(r) = kq/r² for r>c. Equation 4.
We understand that electric potential correlates with the electric field through
V = Ed
A. To compute the potential at the outer surface of the hollow sphere (r=c), we determine that the electric field there is
E = kQ / r²
Then,
V = Ed,
At d = r = c
Thus,
Vc = (kQ / c²) × c
Vc = kQ / c
As a result, the total charge Q consists of +q, -q, and +q
Hence, Q = q - q + q = q
V = kq / c
B. To calculate the potential at the inner surface of the hollow sphere (r=b), we have
V = kQ/r
V = kQ / b, noting that r = b
So, Q = q
V = kq / b
C. At r = a
Following from equation 1:
E(r) = 0 for r≤a. Equation 1
The electric field at the surface of the solid sphere is 0, E = 0N/C
Thus,
V = Ed = 0 V
Consequently, the electric potential at the solid sphere's surface is 0.
D. At r = 0
The electric potential can be determined by
V = kq / r
As r approaches 0,
V = kq / 0
V approaches infinity.
