Answer:
1. Ionic compound- 
2. Polar molecular compound- 
Explanation:
Magnesium (Mg), with atomic number 12, has an electron configuration of 
. The outermost shell possesses 2 electrons, thus it loses these 2 electrons to become 
ions. Bromine (Br), a nonmetal with atomic number 35, has an electron configuration of 
. Its outermost shell holds 7 electrons, allowing it to accept one electron and thus forms 
. Hence, the magnesium ion and bromide ion bond together to form an ionic compound .
Phosphorus (P), also a nonmetal, bonds with bromine covalently. Due to differing electronegativities, they produce polar covalent compounds like .
The energy released results in a kinetic energy of 92.2 keV for the products. We should convert keV into Joules, noting that 1 keV equals a kiloelectron volt. The required conversion is: 1.602×10⁻¹⁹ <span>joule = 1 eV
Kinetic energy = 92.2 keV * (1,000 eV/1 keV) * (</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules
Next, we can determine the velocity of each He atom from the kinetic energy:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
This solves to give us: v = 5.367×10¹¹ m/s
Answer:
0.008945 atm
Explanation:
In the reaction:
2H2S(g) ⇌ 2 H2(g) + S2(g)
Kp is defined as:
Where P represents the pressure of each component at equilibrium.
Starting with an initial pressure of H2S at 3.00 atm, the equilibrium concentrations are:
H2S = 3.00 atm - 2X
H2 = 2X
S2 = X
Substituting these values into the equation gives:
0 = 4X³ - 1.28x10⁻⁶X² + 1.92x10⁻⁶X - 2.88x10⁻⁶
Calculating X yields:
X = 0.008945 atm
In equilibrium, the pressure of S2 is X, so the pressure stands at 0.008945 atm
