Answer:
A balloon will hold a gas volume of 45.0 L at a pressure of 1.35 atm and a temperature of 253 K.
Explanation:
Applying the Ideal Gas Law for the same gas amount, we have:
Parameters are given as follows:
V₁ = 25.0 L
V₂ =?
P₁ = 2575 mm Hg
To convert pressure to atmospheres: P (atm) = P (mm Hg) / 760
P₁ = 2575 / 760 atm = 3.39 atm
P₂ = 1.35 atm
T₁ = 353 K
T₂ = 253 K
Using the earlier formula, we derive:
By solving for V₂, we find:
V₂ = 45.0 L
A balloon will hold a gas volume of 45.0 L at a pressure of 1.35 atm and a temperature of 253 K.
Answer:
Below are the downsides of each electron configuration model:
1). Dot Structures - They consume more space and fail to convey the electron distribution within orbitals.
2). Arrow and line diagrams complicate electron counting and also take up excessive space.
3). Written Configurations do not illustrate electron distribution in orbitals, leading to possible errors in counting electrons.
<span>Response:
A 1.00 L solution that includes 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en).
Contains
0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine.
Using the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts with double that amount of en = 0.000600 mol of en.
Thus, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted leaves 0.00180 mol en unreacted.
According to the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts to yield an equivalent of 0.000300 moles of Cu(en)2^2+
The formation constant Kf for Cu(en)2^2+ is 1x10^20.
Therefore,
1 Cu+2 and 2 en --> Cu(en)2^2+
Kf = [Cu(en)2^2+] / [Cu+2] [en]^2
1x10^20 = [0.000300] / [Cu+2] [0.00180 ]^2
Solving for [Cu+2] gives [Cu+2] = [0.000300] / (1x10^20) (3.24 e-6)
Thus, Cu+2 = 9.26 e-19 Molar.
Since Kf only has 1 significant figure, round that to 9 X 10^-19 Molar Cu+2.</span>
You can test it by combining it with vinegar. The acetic acid present in vinegar reacts with sodium bicarbonate (baking soda) to produce carbon dioxide, resulting in an intense bubbling reaction that is harmless. Baking powder, however, won’t produce this effect.
Answer:
The integer value of x in the hydrate is 10.
Explanation:
Molar concentration of the solution = 0.0366 M
Volume of the solution = 5.00 L
Moles of hydrated sodium carbonate = n
Weight of hydrated sodium carbonate = n = 52.2 g
Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol
By solving for x, we arrive at:
x = 9.95, approximating to 10
The integer x in the hydrate equals 10.
