answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leokris
1 month ago
15

"Enter your answer in the provided box. A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood

plasma with a potassium dichromate solution. The balanced equation is 16H+(aq) + 2Cr2O72−(aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l) If 35.46 mL of 0.05961 M Cr2O72− is required to titrate 28.40 g of plasma, what is the mass percent of alcohol in the blood?"
Chemistry
1 answer:
Tems11 [2.7K]1 month ago
7 0

Answer:

0.1714 (w/w) %

Explanation:

Utilizando la ecuación:

16H+(aq) + 2Cr2O72−(aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l)

Se emplean 2 moles de ion dicromato (Cr₂O₇²⁻) para titular 1 mol de alcohol (C₂H₅OH)

35.46mL = 0.03546L de una solución de Cr₂O₇²⁻ a 0.05961M utilizada para alcanzar el punto de equivalencia en la titulación contiene:

0.03546L ₓ (0.05961 moles Cr₂O₇²⁻ / L) = 2.114x10⁻³ moles Cr₂O₇²⁻

Dado que 2 moles de dicromato reaccionan por cada mol de alcohol, los moles de alcohol en la muestra de plasma son:

2.114x10⁻³ moles Cr₂O₇²⁻ ₓ ( 1 mol C₂H₅OH / 2 moles Cr₂O₇²⁻) = 1.0569x10⁻³ moles de C₂H₅OH

Como la masa molar del alcohol es 46.07g/mol, la masa de alcohol es:

1.0569x10⁻³ moles de C₂H₅OH ₓ (46.07g / mol) = 0.04869g de C₂H₅OH

Por lo tanto, el porcentaje en masa de alcohol en sangre utilizando los 28.40g de plasma es:

(0.04869g de C₂H₅OH / 28.40g) × 100 = 0.1714 (w/w) %

You might be interested in
Explain why CaCl2 is likely to have properties similar to those of CaBr2
Alekssandra [3086]

Answer:

Both CaCl2 and CaBr2 consist of elements (bromine and chlorine) from the same group (group 7).

Explanation:

In the periodic table, elements are arranged into groups based on their valence electron count in the outermost shell. Elements in the same group, which possess a similar number of valence electrons, typically exhibit similar chemical behaviors.

Chlorine and Bromine in CaCl2 and CaBr2 belong to group 7, known as HALOGENS, characterized by having 7 valence electrons in their outer shell.

The similarity in properties between CaCl2 and CaBr2 arises because both contain Chlorine and Bromine, leading to analogous reactions and behaviors when interacting with other compounds.

5 0
2 months ago
How many moles are there in 2.00x10^19 molecules of CCl4?
eduard [2782]

Answer:

Explanation:

A mole is defined as the number of molecules divided by 6.02×10^23

Mole = (2×10^19)/(6.02×10^23)

Mole = 3.32×10^-5 mole

7 0
28 days ago
Why couldn't you substitute 3m H2SO4 for concentrated HNO3 when oxidizing copper?
Alekssandra [3086]

This appears to be an essay question based on an experiment. Different oxidizing agents possess varying strengths. When compared to nitric acid (HNO3), sulfuric acid (H2SO4) serves as a weaker oxidizing agent. Therefore, using H2SO4 in place of HNO3 would not yield the same experimental results.



5 0
12 days ago
Read 2 more answers
How many atoms of Mg are present in 97.22 grams of Mg?
VMariaS [2998]

Answer: The correct choice is (b).

Explanation:

We have the mass of Magnesium at 97.22 g, and the molar mass of Magnesium is 24.305 g/mol.

Therefore, the calculation for the number of moles is as follows.

          Number of moles = \frac{mass given in grams}{Molar mass}

                                 = \frac{97.22 g}{24.305 g/mol}  

                                 = 4 mol

Additionally, it is known that one mole contains 6.023 \times 10^{23} atoms/mol. Thus, we calculate the total number of atoms in 4 moles as follows.

               4 mol \times 6.023 \times 10^{23} atoms/mol

               = 24.08 \times 10^{23} atoms

or,            = 2.408 \times 10^{23} atoms

Hence, we conclude that in 97.22 grams of Magnesium, there are 2.408 \times 10^{23} atoms.

7 0
1 month ago
At –45oC, 71 g of fluorine gas take up 6843 mL of space. What is the pressure of the gas, in kPa?
KiRa [2933]
The quantity of fluorine in moles is calculated as 71/19 = 3.74
We also know that at standard temperature and pressure (273 K and 101.3 kPa), one mole of gas occupies 22.4 liters
So, the volume for 3.74 moles at S.T.P is: 3.74 x 22.4
This results in a volume of 83.776 L, which is equivalent to 83,776 mL

Next, applying Boyle's law, which states that for a fixed amount of gas,
PV = constant

We set up the equation P x 6843 = 101.3 x 83776
Solving for P gives us 1,240 kPa
4 0
1 month ago
Other questions:
  • Convert 3.8 Km/sec to miles/year
    12·1 answer
  • The ship that will transport the terranauts to the core is built of what material?A. Cobalt B. Diamond C. Kryptonite D. Unobtain
    15·1 answer
  • A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce
    10·1 answer
  • in sample of elemental bromine, 55% or the atoms are Br-79, and the remainder are Br-81. if this sample is typical of naturally
    9·1 answer
  • If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m
    5·1 answer
  • vanadium has an atomic mass of 50.9415 amu. it has two common isotopes.one isotopes has a mass of 50.9440 amu and a relative abu
    8·1 answer
  • Two mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,00
    5·1 answer
  • Use the tabulated values of ΔG∘f to calculate E∘cell for the fuel cell breathalyzer, which employs the reaction below. (ΔG∘f for
    5·1 answer
  • 3.51e23 atoms Fe= g Fe
    15·1 answer
  • Determine the number of bonding electrons and the number of nonbonding electrons in the structure of cs2.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!