a) 3.56 x 10^22 N. b) 3.56 x 10^22 N. The sun’s mass is M = 2 x 10^30 kg, while the Earth's mass is m = 6 x 10^24 kg, with a distance of R = 1.5 x 10^11 m separating them. Applying Newton's law for gravitational force F = G (mM / R²), where G = 6.67 × 10^-11 m^3 kg^-1 s^-2 gives us F = 3.56 x 10^22 N. A) The gravitational force by the sun on Earth equates to the force exerted by Earth on the sun, which is also 3.56 x 10^22 N.
It shows a situation where a proton moves perpendicular to a magnetic field of 0.025 tesla. The force acting on the proton has a magnitude of 1.8 × 10⁻¹⁴ newtons, and we need to determine the speed of the proton given q = 1.6 × 10⁻¹⁹ coulombs.
The average velocity of the sled can be expressed with the formula vavg = s/t. Hello! The calculation for average velocity involves determining the distance traveled over time. Thus, vavg = Δx/Δt, where vavg represents average velocity, Δx is the distance traversed, and Δt is the duration of time taken. We know both the distance (s) and the time (t) required for the sled to cover that distance, which allows us to compute the average velocity using the formula vavg = s/t. Wishing you a great day!
The male skater reaches a velocity of 13.71 m/s. According to the principle of conservation of momentum, m1u1 = (m1 + m2)u2, where m1 signifies the mass of the male skater at 78.2 kg, m2 is the mass of the female partner at 48.5 kg, u1 is the male skater's resulting velocity from the push, and u2 is the velocity imparted to the female skater, which was 8.46 m/s. Through the formula, we find u1 = [(78.2 + 48.5) × 8.46] ÷ 78.2, which calculates to 1071.882 ÷ 78.2 resulting in u1 = 13.71 m/s.
Answer: Option D: indicates rapid travel with slow oscillation.
Clarification:
ycarrier(x,t) is traveling quickly but has slow oscillations.