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konstantin123
3 months ago
6

You decide it is time to clean your pool since summer is quickly approaching. Your pool maintenance guide specifies that the chl

orine, Cl2, concentration of the pool should be between 1 and 3 ppm. In order to determine if your pool is safe to swim in, you send a sample of pool water to a chemist for analysis of the Cl2 content. The chemist reports a chlorine concentration of 2.96 × 10–5 M. Convert the concentration of Cl2 to parts-per-million (ppm).
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
4 0

Answer:

Cl2 concentration: 1,048 ppm

Explanation:

Molarity (M) is a unit that indicates how many moles of a substance are in one liter of solution, while ppm is similar to mg/L, representing the mass of the substance per liter. To convert M to ppm, we need to consider both mass and volume. The volume remains in liters in both cases, so no adjustments are needed there. The challenge arises when converting moles from molarity to milligrams for the mg/L conversion to find ppm.

First, we must recognize that the substance in question is Cl2, prompting the need to connect mole quantity to its mass. Referring to the periodic table, we find the atomic weight of Cl is 35.4 g/mole. This relationship allows us to establish moles' mass, as shown in the following equation:

mass=mole*atomic mass

We already know the moles of Cl2 in the solution is (moles=2.96x10^-5). Substituting this value, we can calculate:

m=2,96x10^-5 moles*35,4 g/mole\\ m=1,048x10^-3 g

Keep in mind that we're discussing the mass found per liter of solution, which gives us 1.048x10^-3 g/L. We previously established that ppm equals mg/L, so we need to convert grams to milligrams:

1 g = 1000 mg

Now multiplying both sides by 1.048x10^-3:

1 * 1.048x10^-3 g = 1000 * 1.048x10^-3 mg

Thus, 1,048x10^-3 g translates to 1,048 mg.

This amount of mass detected in one liter indicates that the concentration of the substance in the solution is:

1,048 mg/L

Since we know that mg/L=ppm, the conclusion is:

1,048 ppm

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Explanation:

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An electron is projected with an initial speed of 3.9 × 105 m/s directly toward a proton that is fixed in place. If the electron
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Attached is a document that contains the solution.

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A composite wall separates combustion gases at 2400°C from a liquid coolant at 100°C, with gas and liquid-side convection coeffi
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Response:

\text{heat loss} = 24864.05 \ W/m^2

Clarification:

If

  • T_1, T_2 represent the temperatures of gases and liquids in Kelvins,
  • t_1 and t_2 denote the thicknesses of the gas layer and steel slab in meters,
  • h_1, h_2 are the convection coefficients for gas and liquid in W/m^2 \cdot K,
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then: part(a):

\text{heat loss } = \frac{T_1 - T_2} { \frac{1}{h_1} + \frac{t_1}{t_2} + R_c + \frac{t_2}{k_2} + \frac{1}{h_2}}

by employing known values:

\text {heat loss} = 2486.05 W/m^2

part(b): Utilizing the rate equation:

\text {heat loss} = h_1 (T_1 - T_{s1})

the surface temperature is T_{s1} = 1678.438 \ K

and T_{c1} = T_{s1} - \frac {t_1 (\text{heat loss})}{k_1} = 1664.560 \ K

Correspondingly

T_{c2} = T_{c1} - R_c (\text{heat loss}) = 421.357 \ K

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The temperature profile is depicted in the image provided

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To find power, we must first determine the work done by the force.

1) We will use the following equation to calculate work:

\int\limits {F} \, dx

The force is provided by the problem; our goal is to express 'dx' in terms of 't'

2) It's known that:

\frac{dV}{dt} = a = 2.6

Thus, we have:

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Then:

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After some calculations, the resulting work is:

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