<span>Part b) Find your horizontal distance from the window (answer: 1.5 m)
Part c) Calculate the speed of the ball upon catching it (answer: 8.2 m/s)
I'm confused about what "42 degrees below the horizontal" means. Could someone provide guidance on how to approach this?</span>
Answer:
1.43 x 10¹⁷.
They will move away from each other.
Explanation:
The force acting on each charged sphere is determined as F = mass x acceleration
= 8.55 x 10⁻³ x 25 x 9.8
= 2.095 N
Assuming Q is the charge on each sphere
F = 
Using the values, 2.095 = 
We find that Q² = 
Thus, Q = 2.289 X 10⁻⁶
The quantity of electrons = Charge / charge of a single electron
= 
=1.43 x 10¹³.
They will accelerate away from each other.
Answer:
Electric flux is calculated as 
Explanation:
We start with the given parameters:
The electric field impacting the circular surface is 
Our objective is to ascertain the electric flux passing through a circular region with a radius of 1.83 m situated in the xy-plane. The area vector is oriented in the z direction. The formula for electric flux is expressed as:


Applying properties of the dot product, we calculate the electric flux as:



Consequently, the electric flux for the circular area is
. Thus, this represents the required answer.
1 hour = 3,600 seconds
1 km = 1,000 meters
75 km/hour = (75,000/3,600) m/s = 20-5/6 m/s
The mean speed during the deceleration is
(1/2)(20-5/6 + 0) = 10-5/12 m/s.
Traveling at this average speed for 21 seconds,
the bus covers
(10-5/12) × (21) = 218.75 meters.
Explanation:
The term 'collision' refers to the interaction between two objects. There are two distinct types of collisions: elastic and inelastic.
In this scenario, two identical carts are heading towards each other at the same speed, resulting in a collision. In an inelastic collision, the momentum is conserved before and after the incident, but kinetic energy is lost.
After the event, both objects combine and move together at a single velocity.
The graph representing a perfectly inelastic collision is attached, illustrating that both carts move together at the same speed afterward.