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16 days ago

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Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so

lving for x, and the known values for the system are a=2.55meter/second2, v0=21.8meter/second, and v=0meter/second. Perform the next step in the analysis.

2 answers:

Keith_Richards [1K]16 days ago

7 0

Based on the kinematic formula:

$v^2 = v_o^2 + 2ax$

We have the following known information:

Acceleration a = 2.55 m/s²

$v_0 = 21.8 m/s$

$v = 0$

We want to determine x.

Rearranging the equation, we get:

$0^2 = 21.8^2 + 2(2.55)x$

$0 = 475.24 + 5.1 x$

$x = 93.2 m$

Therefore, the object travels a distance of 93.2 meters.

inna [995]16 days ago

3 0

Answer:

x = -93.18 meters

Explanation:

The equation is:

$v^2=v_o^2+2ax$ ...........(1)

Known values are:

$a=2.55\ m/s^2$

$v_o=21.8\ m/s$

$v=0\ m/s$

Substituting these values into equation (1):

$0=(21.8\ m/s)^2+2\times 2.55\ m/s^2\times x$

The result is x = -93.18 meters

Thus, the value of x is -93.18 meters, which is the required solution.

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Explanation:

Let's analyze the information provided.

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Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙K) and a molar heat capacity at consta

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The amount of heat that enters the gas throughout this two-step process totals 120 cal.

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We are tasked with determining the heat absorbed by the gas at constant pressure

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Next, we calculate the heat absorbed by the gas at constant volume

Using the corresponding heat formula

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Insert the values into the formula

$\Delta H_{1}=3\times4.9\times(300-320)$

$\Delta H_{1}=-294\ cal$

Now, it's necessary to evaluate the total heat flow into the gas during both steps

Using the total heat formula

$\Delta H_{T}=\Delta H_{1}+\Delta H_{2}$

$\Delta H_{T}=414-294$

$\Delta H_{T}=120\ cal$

Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.

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1 day ago

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Answer:

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n= 3.125 x $10^{19$ electrones.

b) La densidad de corriente 'J' en el cable se calcula como

J= I/A => I/πr²

J= 5 / (3.14 x (1.025x $10^{-3$ )²)

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