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forsale
1 month ago
7

Athletic trainers use instant ice packs that can be cooled quickly on demand. Squeezing the pack breaks an inner container, allo

wing two components to mix and react. This reaction makes the pack become cold. Describe the heat flow for this spontaneous process.
Chemistry
1 answer:
KiRa [2.9K]1 month ago
7 0

Answer:

Heat flow is best characterized as the transfer of heat between a system and its surroundings.

Explanation:

Heat is energy that moves spontaneously from a hotter object to a cooler one due to temperature differences among substances. In this scenario, heat can be said to flow from the surroundings, perhaps a hurt athlete's knee, to the ice packs.

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castortr0y [3046]
M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL

From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
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The two-slit diffraction experiment shows how light can be treated as particles and how light waves carry the statistical inform
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The double-slit experiment serves as a renowned method to exemplify concepts in quantum mechanics. Specifically, it highlights the idea of wave-particle duality. Employing a light wave shows diffraction and interference, which are typical characteristics of wave behavior. Unexpectedly, using an electron beam produces an interference pattern as well, indicating that electrons can exhibit wave-like properties.


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Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?
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Which statement explains why sulfur is classified as a Group 16 element?
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Answer: The correct option is (1).

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How much CO2 (L) is produced when 2.10 kg of sodium bicarbonate reacts with excess hydrochloric acid at 25.0 °C and 1.23 atm? A)
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The equation representing the reaction between sodium bicarbonate and hydrochloric acid is as follows:

NaHCO_3_(_s_) + HCl_(_a_q_) \implies NaCl_(_a_q_) + CO_2_(_g_) + H_2O_(_l_)

The substances NaHCO_3 and HCl combine in a 1:1 ratio. Therefore, we calculate the quantity of sodium bicarbonate and its molar mass to determine the moles formed.

NaHCO_3_M_r = 22.99 + 1.008 + 12.011+ 3 \times 16.0= 84.01 g/mol.

2.1kg\ NaHCO_3 \times \frac{1000g}{kg} \times \frac{mol}{84.01g/mol} = 24.997\ mol.

We also recognize that the stoichiometric proportions are 1:1:1:1:1, which leads to the conclusion that the moles of CO_2 equal 24.977 moles.

Next, we apply the ideal gas equation PV=nRT, where P denotes pressure, V refers to volume, R is the gas constant, and T represents the temperature in kelvins. We rearrange to solve for V

PV= nRT \implies V= \frac{nRT}{P}= \frac{ 24.997\ mol \times 8.2507m^3\ atm \times 298.15K }{mol \times K \times 1.23 atm} = 49967\ m^3

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49967\ m^3 \times\frac{L}{1000\ m^3} =49.97L\ CO_2\ produced

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2 months ago
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