<span>Response:
Chlorine has 17 electrons, thus, for 1+ and 2+ ions, we require elements with 18 and 19 electrons, which are argon and potassium: Ar+ and K 2+.
For 1- and 2- ions, we need elements with 16 and 15 electrons, namely sulfur and phosphorus, represented as S- and P 2-.
It’s important to note that + ions indicate electron loss, while - ions reflect electron gain.</span>
3.258 m/s Explanation: The spring constant is assumed to be 263 N/m and the displacement of the spring is also assumed to be 0.7 m; the coefficient of friction between blocks is 0.4. The energy stored in the spring is described by . Given the conservation of energy in the system, the speed of the 8 kg block just prior to collision is 3.258 m/s.
At time 
, the ball's horizontal and vertical velocities can be represented as
However, since the ball is thrown horizontally, we have 
. The horizontal and vertical positions at time are
The ball travels a distance of 22 m horizontally from the throw point, thus
With this, we determine that the time for the ball to reach the ground is
When it touches down, 
and
Answer:
The overall length of the spiral, designated as L, is calculated to be 5378.01 m
Explanation:
Provided information:
Inner radius R1=2.5 cm
and outer radius R2= 5.8 cm.
The thickness of the spiral winding is (d) =1.6 \mu m = 1.6x 10^{-6} m
The total length of the spiral can be computed as
= 5378.01 m
Answer:
Explanation:
Considering that,
The mass of the first vehicle
M1= 328kg
It is traveling in the positive x direction at a speed of
U1 = 19.1m/s
The speed of the second vehicle
U2 = 13m/s, moving in the same direction as the first vehicle..
The mass of the second vehicle
M2 = 790kg
The speed of the second vehicle post-collision
V2 = 15.1 m/s
The speed of the first vehicle following the collision
V1 =?
This represents an elastic collision,
and applying the principle of conservation of momentum
The momentum prior to the collision must equal the momentum afterwards
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The speed of the first vehicle after the collision is 14.04 m/s
