Answer:
a.3.29 m/s
b.3.3 m/s
c.14.8 m
d.15 m
Explanation:
We have the following specifics:
Initial Horizontal speed=
Vertical component of initial speed=
Vertical distance=
a.
Applying the formula and considering g as negative results in 
b.Since the hundredths place exceeds 5, 1 is added to the tenths place, while other digits to the left remain unchanged and the digit to the right is replaced by 0.
c.Horizontal acceleration=
d.The digit in the tenths place at 8 surpasses 5, thus adding 1 to the units place, with all other digits on the left side unchanged and the right-side digit altered to 0.
Horizontal distance=15 m
Electrons are present in all matter. The identification and analysis of cathode rays indicated their nature as subatomic particles, marking the first discovery of electrons. This finding became instrumental in explaining chemical bonds, largely due to the relative ease with which electrons move between atoms.
<span>You are presented with a circuit that includes a 6.0-v battery, a 4.0-ohm resistor, a 0.60 microfarad capacitor, an ammeter, and a switch all connected in series. Your task is to determine the current reading once the switch is closed. Ohm's law should be used, which states V = IR where V signifies voltage, I indicates current, and R represents resistance.</span>
V = IR
I = V/R
I = 6 volts / 4 ohms
I = 1.5A
Upon closing the switch, the cathode side plate starts accumulating electrons if it was previously empty. As this process continues, the current diminishes. Eventually, when the capacitor reaches its maximum electron retention, the current will cease. An increased capacitance means a greater capacity for electron storage.
Explanation:
Please refer to the attachment for the solution.
Response:
(b) 10 Wb
Clarification:
Given;
angle of the magnetic field, θ = 30°
initial area of the plane, A₁ = 1 m²
initial magnetic flux through the plane, Φ₁ = 5.0 Wb
The equation for magnetic flux is;
Φ = BACosθ
where;
B denotes the magnetic field strength
A represents the area of the plane
θ is the inclination angle
Φ₁ = BA₁Cosθ
5 = B(1 x cos30)
B = 5/(cos30)
B = 5.7735 T
Next, calculate the magnetic flux through a 2.0 m² section of the same plane:
Φ₂ = BA₂Cosθ
Φ₂ = 5.7735 x 2 x cos30
Φ₂ = 10 Wb
<pHence, the magnetic flux through a 2.0 m² area of the same plane is
10 Wb.Option "b"
