A sonar device on a ship sends ultrasound waves under the water to locate a sunken ship. It takes the ultrasound wave 0.6 second

Answer:

Δx=(v+v0/2)t

Explanation:

We can determine which kinematic equation to apply by selecting the one that encompasses the known variables as well as the unknown we aim to solve for.

In this scenario, the unknown we wish to determine is the initial velocity v_0v

0

​  v, start subscript, 0, end subscript of the roller coaster.

Answer:

Explanation:

An image of the bond resulting from the search is attached.

Consider the force directed towards thymine as negative.

For the O-H-N combination:

The resulting force from this combination is:

In the case of the N-H-N combination:

The total force acting from this combination is:

The force that thymine applies on adenine is:

When rounded to three significant figures, the net force is

b)

The negative value indicates that the force is attractive, as it is aimed towards thymi.

c)

The force acting on the electron due to the proton is:

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.

d)

The ratio of the above forces is:

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.

Answer:

b. The loop's current consistently flows in a counterclockwise direction.

Explanation:

As a magnet descends through a wire loop, it generates an induced current within that loop. This induced current arises due to the magnet's movement, leading to a variation in magnetic flux. Lenz's law states that the induced current will act to counteract the change that produces it. In this scenario, the only feasible resistance to the magnet’s fall is through inducing a similar pole on the loop to counteract its downward motion. An induced current that circulates counterclockwise in the wire loop mimics the polarity of a northern pole, thereby repelling the magnet's descent. Furthermore, as the magnet passes the wire loop, this induced north pole will seek to attract the magnet's south end in an effort to halt its downward progression.

Answer:

  v₂ = v/1.5 = 0.667 v

Explanation:

We will apply the conservation of momentum for this problem, defining a system that includes both students and their carts; the forces during contact are considered internal, ensuring momentum is conserved.

Initial momentum before the push

p₀ = 0

Final momentum after the push yields

    = m₁ v₁ + m₂ v₂

   0 = m₁ v₁ + m₂ v₂

   m₁ v₁ = - m₂ v₂

Substituting yields

   M (-v) = -1.5M v₂

   v₂ = v / 1.5

  v₂ = 0.667 v

The frequency is calculated to be 735 Hz. Given: Person's distances to speakers are r₁ = 4.1 m and r₂ = 4.8 m. The path difference calculates to d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m. In terms of destructive interference, we derive: λ = v/f, where v is the sound speed of 343 m/s. Using n = 1 gives f = 245 Hz, and for n = 3, f = 735 Hz. Thus, the second lowest frequency for destructive interference is 735 Hz.