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1 month ago

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Most calculators operate on 6.0 V. If, instead of using batteries, you obtain 6.0 V from a transformer plugged into 110-V house

wiring, what must the ratio of the primary to the secondary turns be in the transformer? (Ignore any changes in voltage due to rectification.)

1 answer:

kicyunya [3.2K]1 month ago

6 0

1/0.0545. The transformation ratio of primary coil turns to secondary coil turns is directly proportional to the voltage transformation occurring. With 6.0 V on the secondary side (output) and 110 V on the primary side (input), the voltage ratio is calculated as 6/110 = 0.0545. This means for each turn in the primary coil, there are 0.0545 turns in the secondary coil.

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Joan and Mike's teacher show them a picture of an atom and ask them to identify it using the periodic table. Joan says the atom

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Since we can't see the image the teacher has provided, we must deduce its content based on clues from the answer choices. The image likely illustrates an atom containing 3 protons and 3 neutrons in the nucleus, along with 3 electrons orbiting it. If that is the case, Mike is correct (first choice) because the atomic number indicates the number of protons present in an atom. Since there are 3 protons, it corresponds to lithium, which has an atomic number of 3. The second choice is false, as electrons do not factor into atomic mass. The third and fourth options are also incorrect; regrettably, Joan does not grasp the concepts accurately.

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1 month ago

An electron moves in a region where the magnetic field is uniform and has a magnitude of 80 μT. The electron follows a helical p

Softa [3030]

Answer:

3.4 x 10⁴ m/s

Explanation:

Analyze the circular path of the electron

B = magnetic field = 80 x 10⁻⁶ T

m = mass of an electron = 9.1 x 10⁻³¹ kg

v = speed in the radial direction

r = radius of the circular trajectory = 2 mm = 0.002 m

q = charge of an electron = 1.6 x 10⁻¹⁹ C

For the electron’s circular movement

qBr = mv

(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v

v = 2.8 x 10⁴ m/s

Now, consider the electron's movement in a straight line:

v' = speed in linear motion

x = distance traveled horizontally = 9 mm = 0.009 m

t = duration = $\frac{2\pi m}{qB}$ = $\frac{2\pi (9.1\times 10^{-31})}{(1.6\times 10^{^{-19}})(80\times 10^{-6})}$ = 4.5 x 10⁻⁷ sec

Using the formula

x = v' t

0.009 = v' (4.5 x 10⁻⁷)

v' = 20000 m/s

v' = 2 x 10⁴ m/s

The resultant speed is given by

V = sqrt(v² + v'²)

V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)

v = 3.4 x 10⁴ m/s

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1 month ago

Read 2 more answers

A spin bike has a flywheel in two parts—a 12.5 kg disk with radius 0.23 m, and a 7.0 kg ring with mass concentrated at the outer

Keith_Richards [3271]

Response:

Clarification:

Provided

weight of disk $m=12.5 kg$

diameter of disc $R=0.23 m$

weight of ring $m_r=7 kg$

Force $F=9.7 N$

$N=180 rpm$

$\omega =\frac{2\pi N}{60}$

$\omega =6\pi rad/s$

Overall moment of inertia

=Disc's moment of inertia +Ring's Moment of Inertia

$=0.5\cdot 12.5\times 0.23^2+7\times 0.23^2$

$=13.25\times 0.23^2=0.7009 kg-m^2$

At this point, Torque is $T=F\times R=I\cdot \alpha$

$9.7\times 0.23=0.7\times \alpha$

$\alpha =3.18 rad/s^2$

Utilizing $\omega _f=\omega +\alpha t$

$\omega _f=0$ in this scenario

$0=6\pi -3.18\times t$

$t=\frac{6\pi }{3.18}$

$t=5.92 s$

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1 month ago

a hippopotamus produces a pressure of 250000 pa when it is standing on all four feet if the weight of the hippo is 40000 N what

Maru [3345]

0.04m²

Explanation:

Known values:

Pressure = 250000Pa

Weight = 40000N

Unknown:

Area of each foot =?

Solution:

Pressure is defined as the force applied per unit area of an object

Pressure = $\frac{force}{area}$

To determine the area;

Area = $\frac{force }{pressure}$

Area = $\frac{40000}{250000}$ = 0.16m²

The force exerted by all four feet amounts to 0.16m²

thus, the area for each foot is $\frac{0.16}{4}$ = 0.04m²

Learn more:

Pressure

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1 month ago