An MRI machine needs to detect signals that oscillate at very high frequencies. It does so with an LC circuit containing a 15mH

a) 3.56 x 10^22 N. b) 3.56 x 10^22 N. The sun’s mass is M = 2 x 10^30 kg, while the Earth's mass is m = 6 x 10^24 kg, with a distance of R = 1.5 x 10^11 m separating them. Applying Newton's law for gravitational force F = G (mM / R²), where G = 6.67 × 10^-11 m^3 kg^-1 s^-2 gives us F = 3.56 x 10^22 N. A) The gravitational force by the sun on Earth equates to the force exerted by Earth on the sun, which is also 3.56 x 10^22 N.

Response:

(e) thermal expansion

Clarification:

The density, heat of fusion, and melting temperature of a metal are critical factors to consider when increasing its temperature from room temperature to its melting point. These will dictate the following aspects:

Density: refers to the ratio between a body's mass and the space it occupies in the universe.

Heat of fusion: The enthalpy of fusion or heat of fusion signifies the amount of energy required to cause a mole of an element at its melting point to transition from solid to liquid state, under constant pressure.

Melting temperature is defined as the thermal level at which the phase change from solid to liquid takes place under standard atmospheric pressure.

On the other hand, the dilution of metals only influences the volume they will occupy without affecting the heating process

Answer:

The electric flux going through the sphere is

Explanation:

Given

Required

Calculate the electric flux

Electric flux can be computed using the formula;

Ф = q/ε

Where ε stands for the electric constant permittivity

ε

Substituting ε and ; the formula simplifies to

Ф =

Ф =

Ф =

Ф =

Ф =

Ф =

Ф =

Ф =

Thus, the electric flux through the sphere is

Answer:

change in KE = -12.95 Btu

Explanation:

provided data

mass = 3000-lbm

initial velocity of vehicle vi = 10 mph = 14ft/s

final velocity of vehicle vf = 0 mph = 0 ft/s

solution

the crumple zone is designed to absorb kinetic energy upon impact

thus the change in KE is related to the initial and final speeds, expressed as:

change in KE = 0.5 × m × (vf² - vi² ).................1

Substituting in the parameters yields:

change in KE = 0.5 × 3000 × (0² - 14.7² )

change in KE = -324135 × *  

change in KE = -12.95 Btu

Answer:The tension on either side of the cable is 3677.57 N

Explanation:

given data

traffic light = 20 kg

cable spanning between two poles = 30 m

sag of the cable = 0.40 m

solution

through the free body diagram

tan θ = .............1

θ = 1.527 °

and

tension = mg

The horizontal net force can be stated as

T2 cosθ = T1 cosθ.................2

and

thus T2 - T1..............3

and

in the vertical axis we express as

( T1 + T2) sinθ = mg...................4

therefore using equation 3 here

2 × T1 sin(1.527) = 20 × 9.8

T1 = 3677.57 N