a) 3.56 x 10^22 N. b) 3.56 x 10^22 N. The sun’s mass is M = 2 x 10^30 kg, while the Earth's mass is m = 6 x 10^24 kg, with a distance of R = 1.5 x 10^11 m separating them. Applying Newton's law for gravitational force F = G (mM / R²), where G = 6.67 × 10^-11 m^3 kg^-1 s^-2 gives us F = 3.56 x 10^22 N. A) The gravitational force by the sun on Earth equates to the force exerted by Earth on the sun, which is also 3.56 x 10^22 N.
Response:
(e) thermal expansion
Clarification:
The density, heat of fusion, and melting temperature of a metal are critical factors to consider when increasing its temperature from room temperature to its melting point. These will dictate the following aspects:
Density: refers to the ratio between a body's mass and the space it occupies in the universe.
Heat of fusion: The enthalpy of fusion or heat of fusion signifies the amount of energy required to cause a mole of an element at its melting point to transition from solid to liquid state, under constant pressure.
Melting temperature is defined as the thermal level at which the phase change from solid to liquid takes place under standard atmospheric pressure.
On the other hand, the dilution of metals only influences the volume they will occupy without affecting the heating process
Answer:
The electric flux going through the sphere is 
Explanation:
Given

Required
Calculate the electric flux
Electric flux can be computed using the formula;
Ф = q/ε
Where ε stands for the electric constant permittivity
ε 
Substituting ε
and
; the formula simplifies to
Ф = 
Ф = 
Ф = 
Ф = 
Ф = 
Ф = 
Ф = 
Ф = 
Thus, the electric flux through the sphere is 
Answer:
change in KE = -12.95 Btu
Explanation:
provided data
mass = 3000-lbm
initial velocity of vehicle vi = 10 mph = 14ft/s
final velocity of vehicle vf = 0 mph = 0 ft/s
solution
the crumple zone is designed to absorb kinetic energy upon impact
thus the change in KE is related to the initial and final speeds, expressed as:
change in KE = 0.5 × m × (vf² - vi² ).................1
Substituting in the parameters yields:
change in KE = 0.5 × 3000 × (0² - 14.7² )
change in KE = -324135 ×
*
change in KE = -12.95 Btu
Answer:The tension on either side of the cable is 3677.57 N
Explanation:
given data
traffic light = 20 kg
cable spanning between two poles = 30 m
sag of the cable = 0.40 m
solution
through the free body diagram
tan θ =
.............1
θ = 1.527 °
and
tension = mg
The horizontal net force can be stated as
T2 cosθ = T1 cosθ.................2
and
thus T2 - T1..............3
and
in the vertical axis we express as
( T1 + T2) sinθ = mg...................4
therefore using equation 3 here
2 × T1 sin(1.527) = 20 × 9.8
T1 = 3677.57 N