Answer:
The change in linear momentum of the ball amounts to 6 kg-m/s.
Explanation:
Provided that,
Ball mass, m = 1 kg
Initial ball speed, u = 3 m/s
Upon striking a wall, it rebounds, moving horizontally to the opposite side at the same speed of 3 m/s, thus v = -3 m/s
The change in linear momentum is calculated as follows:
Consequently, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.
To address this question, we will utilize concepts linked to centripetal force, aligning it with the static frictional force acting on the object. Using this relationship, we can derive the velocity and input the known values. The defined values are:
The maximum velocity can be determined using centripetal force,
Should be equal to,
As a result, the highest speed achievable through the arc without slipping is 9.93m/s
Answer:
The answer to your inquiry is Mass = 41230.7 g or 41.23 kg.
Explanation:
Data
Density = 0.737 g/ml
Mass = ?
Volume = 14.9 gal
1 gal = 3.78 l
Process
1.- Convert gallons to liters
1 gal ---------------- 3.78 l
14.9 gal ------------- x
x = 56.44 l
2.- Convert liters to milliliters
1 l ------------------- 1000 ml
56.44 l --------------- x
x = (56.44 x 1000) / 1
x = 56444 ml
3.- Calculate the mass
Formula
Density =
Solving for mass
Mass = density x volume
Substituting values
Mass = 0.737 x 56444
Result
Mass = 41230.7 g or 41.23 kg.
The entire and thorough solution is included.
