Which of the following statements are true about an object in two-dimensional projectile motion with no air resistance? (There c

Answer:

The amount of heat that enters the gas throughout this two-step process totals 120 cal.

Explanation:

Given that,

Moles present = 3

Heat capacity at volume held constant = 4.9 cal/mol.K

Heat capacity at pressure held constant = 6.9 cal/mol.K

Starting temperature = 300 K

Ending temperature = 320 K

We are tasked with determining the heat absorbed by the gas at constant pressure

Employing the heat formula

Substituting the values into the equation

Next, we calculate the heat absorbed by the gas at constant volume

Using the corresponding heat formula

Insert the values into the formula

Now, it's necessary to evaluate the total heat flow into the gas during both steps

Using the total heat formula

Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.

To address this question, we will utilize concepts linked to centripetal force, aligning it with the static frictional force acting on the object. Using this relationship, we can derive the velocity and input the known values. The defined values are:

The maximum velocity can be determined using centripetal force,

Should be equal to,

As a result, the highest speed achievable through the arc without slipping is 9.93m/s

Answer:

Jari

Explanation:

To determine who is traveling faster, we need to evaluate their gradients. A steeper slope indicates a higher speed.

For Jari's path, starting point is (0, 0) and (6, 7) is another point.

The gradient is the difference in y divided by the difference in x:

Change in y=7-0=7

Change in x=6-0=6

Thus, the slope equals 7/6.

For Jade, her first point is (0, 10) and another is (6, 16).

Change in y=16-10=6

Change in x=6-0=6

Thus, the slope equals 6/6=1.

It's evident that 7/6 exceeds 6/6 or 1, proving Jari is quicker than Jade.

Answer:

Explanation:

Consider the following:

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field measured at point P

Thus,

Now, by applying integration to the equation above

Answer

Data provided:

mass of the block = 200 g = 0.2 Kg

Velocity at A = 0 m/s

Velocity at B = 8 m/s

distance of slide = 10 m

height of the block = 4 m

calculation for the block's potential energy

    P = m g h

    P = 0.2 x 9.8 x 4

    P = 7.84 J

kinetic energy calculated as

Work done = P - KE

work = 7.84 - 6.14

work = 1.7 J

b) using the formula v² = u² + 2 a s

   0 = 8² - 2 x a x 10

   a = 3.2 m/s²

ma - μ mg = 0