2 months ago

An object is placed 12.5 cm from a lens of focal length 22.0 cm. What is the image distance?

Physics

1 answer:

Sav [3.1K]2 months ago

6 0

Response:11.5

Clarification:

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Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a

ValentinkaMS [3465]

Conclusion:

The total net force acting on the objects is 16 N, directed towards the right.

Clarification:

It is stated that,

The force exerted by the dog, $F_1 = 32\ N$ (to the right)

The force exerted by Simone, $F_2 = -16\ N$ (backward)

Here, assume the backward direction is negative and the right direction is positive.

The net force will move in the direction where the larger force is present. The net force can be calculated as:

$F=F_1+F_2$

$F=32+(-16)$

F = 16 N

Thus, the net force amounts to 16 N, acting towards the right.

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2 months ago

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A rocket starts from rest and moves upward from the surface of the earth. for the first 10.0 s of its motion, the vertical accel

kicyunya [3294]

The rocket's acceleration is described here as

$a_y = 2.60* t$

now recognizing that

$\frac{dv}{dt} = 2.60t$

we integrate both sides

$\int dv = \int 2.60t dt$

$v = 2.60\frac{t^2}{2}$

$v = 1.30 t^2$

given that the rocket is accelerating for a duration of t = 10 s

thus, we have

$v = 1.30 * 10^2$

$v = 130 m/s$

consequently, after t = 10 s, the rocket will achieve a speed of 130 m/s in an upward direction

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1 month ago

Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.

ValentinkaMS [3465]

Response: The result would be no reaction.

Clarification:

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2 months ago

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