The compound is acetone ( CH₃-CO-CH₃)
Explanation:
1) Acetone is represented as CH₃-CO-CH₃.
2) This is a molecule formed by covalent bonds.
3) When it dissolves, compounds with covalent bonds remain as individual molecules, indicating that the primary species in the solution are the molecules themselves, which are surrounded (solvated) by water molecules.
In contrast, ionic compounds ionize. For example, when NaCl dissolves in water, it completely breaks down into ions, hence the predominant species are the ions Na⁺ and Cl⁻, rather than the NaCl formula.
This leads to the conclusion that: when acetone dissolves in water, the primary components are the acetone molecules (there is no need to mention that water molecules are in the solution, as that isn't the question's focus).
The mass of KBr required is 16.7 g. This concludes from a volume of 0.400 L and a concentration of 0.350 M. Utilizing the molarity formula, moles are calculated as 0.14, leading to a molecular weight calculation of 119 g/mol, thus resulting in a mass of 16.7 g of KBr.
The unknown acid is identified as either butanoic acid or ascorbic acid. To ascertain the number of moles based on the given molarity, we utilize the following relationship: Molarity of NaOH solution = 0.570 M and Volume of solution = 39.55 mL. Utilizing the values in the provided equation, we derive the necessary data. The equation governing NaOH and monoprotic acid reactions indicates that one mole of NaOH reacts with one mole of HX, resulting in 0.0225 moles of the monoprotic acid. Conversely, in the case of NaOH and diprotic acid interactions, the stoichiometry is such that two moles of NaOH engage with one mole of diprotic acid. Consequently, we can calculate moles for butanoic acid with a mass of 2.002 g and a molar mass of 88 g/mol, leading us to the conclusion that both butanoic and ascorbic acids represent the unknown acid being neutralized.
extinction coefficient (ε) = 347 L·mol⁻¹·cm⁻¹. The chemical equation representing the reaction of chromium (Cr) with hydrochloric acid (HCl) is: 2 Cr + 6 HCl → 2 CrCl₃ + 3 H₂. To find the number of moles, we apply the formula: number of moles = mass / molar weight. For chromium, we calculate: number of moles of Cr = 0.3 × 10⁻³ (g) / 52 (g/mole), leading to number of moles of Cr = 5.77 × 10⁻⁶ moles. Examining the reaction, we observe that 2 moles of Cr yield 2 moles of CrCl₃, hence 5.77 × 10⁻⁶ moles of Cr will also produce 5.77 × 10⁻⁶ moles of CrCl₃. The molar concentration is determined by: molar concentration = number of moles / volume (L), thus molar concentration of CrCl₃ = 5.77 × 10⁻⁶ / 10 × 10⁻³, which equals 5.77 × 10⁻⁴ moles/L. To convert percent transmittance (%T) to absorbance (A), we use the equation A = 2 - log(%T). Therefore, A = 2 - log(62.5), leading to A = 0.2. The relationship defining absorbance (A) includes the extinction coefficient (ε), path length (l), and concentration (c): A = εlc, hence ε = A / lc, giving ε = 0.2 / (1 × 5.77 × 10⁻⁴), which results in ε = 0.0347 × 10⁴. Thus, the extinction coefficient is ε = 347 L·mol⁻¹·cm⁻¹.
The total number of moles of oxygen contained in the sample is 11.3 moles. Explanation: Based on the stoichiometry of the compound, 1 mole of
corresponds with 4 moles of CO or can be stated as 1 mole containing 1 mole of Ni, 4 moles of C, and 4 moles of O, leading to the conclusion that moles of C and O are equal. Therefore, since there are 11.3 moles of carbon present, there are likewise 11.3 moles of oxygen.
