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Vsevolod
1 month ago
9

Lecithins are glycerophospolipids (phosphoglycerides) containing choline, (CH3)3N CH2CH2OH. Draw a lecithin with stearic acid, C

H3(CH2)16COOH, at carbon 1 and oleic acid, CH3(CH2)7CH=CH(CH2)7COOH, at carbon 2.

Chemistry
2 answers:
KiRa [2.9K]1 month ago
8 0
Refer to the image provided for the solution. Essentially, you need to break the double bond between the Carbons and incorporate Hydrogens to satisfy the octet configuration.

Thanks to my colleague who assisted me with this issue!

lorasvet [2.7K]1 month ago
5 0

The response is found in the Word document attached below.

In the illustration of lecithin:

1) The alcohol glycerol part is depicted in purple.

2) The choline and phosphate components are shown in orange.

3) Stearic acid (the saturated fatty acid) is marked in red.

4) Oleic acid (the monounsaturated fatty acid) is highlighted in green.

Lecithin is a fatty substance that appears yellow-brown and is found in both animal and plant tissues.

Download docx
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A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.
VMariaS [2998]

Response:

2200 mg of antibiotic

Explanation:

The prescribed antibiotic dosage is 40 mg/kg of body weight.

For a patient weighing 55 kg, we calculate the dose of antibiotic as follows:

If we analyze 40/1000000, we can determine antibiotic allocation in kg per kg of weight

= 0.00004 kg of antibiotic for each kilogram

0.00004 multiplied by 55 (to find out the required amount for a 55 kg individual)

= 0.0022 kg

This 0.0022 figure converts to milligrams as follows

0.0022*10^6

= 2200 mg of antibiotic is indicated for a patient weighing 55 kg.

4 0
14 days ago
Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °
VMariaS [2998]

The change in temperature can be expressed as:

T_2-T_1=\dfrac{q}{mC_p(Gold)}

By substituting in the known values, we arrive at:

T_2-T_1=\dfrac{70\ cal}{20\ g\times 0.0310\ cal/g^o\ C}\\\\T_2-T_1=112.90^oC\\\\T_2-35^oC=112.90^oC\\\\T_2=(112.90+35)^oC\\\\T_2=147.9^oC

Thus, we obtain the required answer.

6 0
27 days ago
Based on the crystal-field strengths cl- < f- < h2o < nh3 < h2nc2h4nh2, which octahedral ti (iii) complex below has
eduard [2782]
<span>According to crystal field strength, the Cl ligand results in the longest d-d transition when coordinated with Ti(III) due to its classification as a weak field ligand that causes minimal d orbital splitting.</span>
8 0
21 day ago
Acetone major species present when dissolved in water
Alekssandra [3086]

The compound is acetone ( CH₃-CO-CH₃)


Explanation:


1) Acetone is represented as CH₃-CO-CH₃.


2) This is a molecule formed by covalent bonds.


3) When it dissolves, compounds with covalent bonds remain as individual molecules, indicating that the primary species in the solution are the molecules themselves, which are surrounded (solvated) by water molecules.


In contrast, ionic compounds ionize. For example, when NaCl dissolves in water, it completely breaks down into ions, hence the predominant species are the ions Na⁺ and Cl⁻, rather than the NaCl formula.


This leads to the conclusion that: when acetone dissolves in water, the primary components are the acetone molecules (there is no need to mention that water molecules are in the solution, as that isn't the question's focus).



3 0
1 month ago
The boiling point of another member of this homologous series was found to be 309 KK. What is the likely molecular formula for t
KiRa [2933]

Answer: Pentane C5H12

Explanation:

The boiling point is defined as the temperature at which a liquid's vapor pressure matches the external pressure, causing the liquid to turn into vapor.

This compound is likely Pentane, represented as C5H12, since its boiling point falls between that of Butane, with the formula C4H10, and Hexane, with the formula C6H14.

8 0
1 month ago
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