Consider the reaction below. 2H2O 2H2 + O2 How many moles of hydrogen are produced when 6.28 mol of oxygen form?

What is the emperical formula for a compound containing 68.3% lead, 10.6% sulfur, and the remainder oxygen? a. Pb2SO4 b. PbSO3 c

Tems11 [2403]

Solution:

The molecular formula is PbSO₄, indicating lead sulfate

Option c.

Explanation:

The percentage makeup shows that in 100 g of this compound, there are:

68.3 g of Pb, 10.6 g of S, and (100 - 68.3 - 10.6) = 21.1 g of O

To find the moles of each element, we divide by their molar masses:

68.3 g Pb / 207.2 g/mol = 0.329 moles Pb

10.6 g S / 32.06 g/mol = 0.331 moles S

21.1 g O / 16 g/mol = 1.32 moles O

Next, we find the mole ratio by dividing each by the smallest number of moles:

0.329 / 0.329 = 1 Pb

0.331 / 0.329 = 1 S

1.32 / 0.329 = 4 O

Thus, the molecular formula is PbSO₄, representing lead sulfate.

8 0

20 days ago

Read 2 more answers

65g of nitric acid are produced in a reaction. 2.5g of platinum are added to the reaction vessel at the start of the reaction to

alisha [2718]

Answer:

2.5 g of platinum

Explanation:

A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.

Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.

6 0

1 month ago

An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decompo

lions [2653]

Answer:

The rate law for the decomposition reaction is:

$R=k[D]^2$

The unit for the rate constant will be $M^{-1}s^{-1}$

Explanation:

$D\rightarrow Product$

The rate law can be expressed as:

$R=k[D]^x$ ..[1]

When the drug concentration is tripled, the decomposition rate rises by a factor of nine.

$[D]'=3[D]$

$R'=9\times R$

$R'=k[D]'^x$ ...[2]

[1] ÷ [2]

$\frac{R}{R'}=\frac{k[D]^x}{k[D']^x}$

$\frac{R}{9R}=\frac{k[D]^x}{k[3D]^x}$

$9=3^x$

Solving for x results in:

x = 2.

This indicates a second-order reaction.

The decomposition reaction's rate law is:

$R=k[D]^2$

The unit for the rate constant will be:

$k=\frac{R}{[D]^2}=\frac{M/s}{(M)^2}=M^{-1}s^{-1}$

The unit for the rate constant will be $M^{-1}s^{-1}$ .

5 0

1 month ago

A solution is 0.10 M in Pb(NO3)2 and 0.10 M in AgNO3. Solid NaI is added until the second solid compound is on the verge of prec

Tems11 [2403]

The first compound to precipitate will be AgI. Explanation: To form a precipitate from a salt solution, the ionic product must surpass the solubility product. Given that AgI has a significantly low Ksp, it will precipitate before PbI2 does. The concentration of AgI solution also affects precipitation speed; the highest concentration of AgI in the choices provided is...

4 0

22 days ago

A laboratory analysis of an unknown sample yields 74.0% carbon, 7.4% hydrogen, 8.6% nitrogen, and 10.0% oxygen. What is the empi

Tems11 [2403]

Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO

3 0

1 month ago