The combined mass of Laura and the sled sums up to 887.5 kgExplanation: To compute the total weight from Laura's weight plus the drag on the sled, we can determine the force as follows: =(400 + 310) N = 710 N. According to Newton's second law of motion, ''the rate of change of momentum is directly related to the force applied.'' Here, m represents Laura's mass and m the sled's mass. Thus, the combined mass is calculated as follows: given V = Δv = 4-0 = 4m/s, with t = 5 s. Consequently, the mass of Laura and the sled together results in 887.5 kg.
Clarification:
Let T signify the pendulum's period. The time's SI unit is seconds (s).
It is influenced by the length of the pendulum, l, and the gravitational acceleration, g.
The SI units for gravitational acceleration, g, and pendulum length, l, are m/s² and m, respectively.
Dividing m by m/s² produces s². Taking the square root of s² results in s, which is the SI unit for the pendulum's period.
Thus,

This concludes the solution we sought.
Refer to the diagram below.
This discussion operates under a basic analysis that overlooks air resistance and variations in the terrain the missile traverses.
Let V₀ be the launch velocity, at an angle θ to the horizontal.
The horizontal velocity component equals V₀ cosθ.
If the flight duration is

, then

where r represents the missile's range.
The time t at which the missile is at ground level is expressed by

where g signifies acceleration due to gravity.
t = 0 signifies the missile's launch. Thus

Consequently,

Typically, an angle of θ=45° is optimal for achieving maximum range, resulting in

This discussion applies more accurately to a scud missile than to a powered, guided missile.
Response:

Usually, θ=45°
Answer:
17 m/s south
Explanation:
Mass of the dog = 10 kg
Mass of skateboard = 2 kg
v = Combined velocity = 2 m/s
Velocity of the dog = 1 m/s
Velocity of skateboard
In this scenario, linear momentum is conserved

The speed of the skateboard post-dog jump will be 17 m/s south, considering north as the positive direction
There's an absence of circuit diagrams.
Initially, this causes worry for a moment, until we remember that we have no understanding of the experiment mentioned in the problem either, rendering such worries unnecessary.