Which statement about the spectrophotometric analysis of Red 40 dye is TRUE?

Answer:

Positron emission

Explanation:

In positron emission, a proton transforms into a neutron. This alteration results in a daughter nucleus with its mass number increased by 1, while the atomic number remains unchanged. The formation of a new neutron boosts the neutron count in the daughter nucleus, thus enhancing the N/P ratio.

Concurrently, a positron is emitted along with an anti-neutrino to ensure spin conservation.

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the molecules:

The overall width of a crystal measured in millimeters=

The overall width of a crystal is 1.65 mm.

Answer:

The new gas pressure within the chamber registers at 1,093.75 mmHg

Explanation:

The Gay-Lussac Law establishes a relationship between a gas's pressure and temperature when volume remains constant. This principle asserts that gas pressure is directly tied to its temperature: as temperature increases, pressure rises, and conversely, as temperature falls, pressure also diminishes. Therefore, the Gay-Lussac law can be depicted mathematically as:

Given an initial and final state of gas, we can apply the following formula:

In this scenario:

• P1= 1560 mmHg
• T1= 445 K
• P2=?
• T2= 312 K

Calculating:

P2=1,093.75 mmHg

The new gas pressure inside the chamber is 1,093.75 mmHg

To find the answer, start by calculating the total mass of the copper utilized:

Copper used = 100 pennies x 3.0g Cu per penny = 300.0 g Cu

Next, identify the path and molar ratios from Cu produced back to CuFeS2 needed using the established balanced reactions:

1 Cu2S from 2 CuS; 2Cu from 1 Cu2S; 2CuS from 2CuFeS2
Thus, 2Cu comes from 2CuFeS2, indicating a 1:1 molar ratio.

Then convert grams of Cu to moles and grams of CuFeS2:
= 300.0 g Cu * 1 mol Cu/63.546g Cu * 2 mol CuFeS2/2 moles Cu

= 4.72 moles CuFeS2

The required amount of chalcopyrite mined = 4.72 moles CuFeS2 * 183.54 g CuFeS2/1 mole CuFeS2 = 866.49 g CuFeS2