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Ksenya-84
22 days ago
11

A metal surface becomes dull because of continued abrasion physical change or chemical

Chemistry
1 answer:
lorasvet [2.5K]22 days ago
6 0
It must be a physical change unless a chemical substance interacts with the metal surface, resulting in a chemical change.
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A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state.Th
castortr0y [2808]
The answer is C. The specific amount of energy released when excited electrons fall back to the ground state produces an emission spectrum. That energy is emitted as photons with precise wavelengths corresponding to the energy differences between levels. Because each element yields a characteristic set of wavelengths, the emission spectrum can be used to identify the element in the sample.
5 0
14 days ago
Read 2 more answers
A solution with 117 grams of lithium hydroxide and another with 141 grams of hydrogen bromide are combined. They react according
Tems11 [2445]

Answer: C. 151 g

Solution: The balanced equation given is:

LiOH+HBr\rightarrow LiBr+H_2O

From this equation, the ratio of moles between all substances is 1:1. We have 117 grams of LIOH and 141 grams of HBr available and need to calculate the theoretical yield of LiBr.

We should convert each reactant’s grams into moles to identify the limiting reagent since the theoretical yield relies on it.

Molar mass for LiOH = 6.94 + 15.999 + 1.008 = 23.947 grams per mole

Molar mass for HBr = 1.008 + 79.904 = 80.912 grams per mole

To find the moles of each reactant, we divide their grams by their respective molar masses.

Moles of LiOH = 117gLiOH(\frac{1mol}{23.947}) = 4.89 mol

Moles of HBr = 141gHBr(\frac{1mol}{80.912g}) = 1.74 mol

As there are fewer moles of HBr, it is the limiting reactant. With a 1:1 mol ratio between HBr and LiBr, 1.74 moles of LiBr can be produced.

Molar mass of LiBr = 6.94 + 79.904 = 86.844 grams per mole

The mass of LiBr formed = 1.74molLiBr(\frac{86.844g}{1mol}) = 151 g LiBr

Based on calculations, the theoretical yield of LiBr is 151 g, hence the correct answer is C.


4 0
1 month ago
How many moles of carbon are in 7.87x10^7 carbon molecules?
Anarel [2637]
There are 6.022*10^23 molecules in one mole of carbon. To find out how many moles correspond to 7.87*10^7 molecules, we let the number of moles be represented by ‘x’. From this, we establish a ratio: 1 mole corresponds to 6.022*10^23 molecules, while x moles correspond to 7.87*10^7 molecules. Using cross multiplication, we derive x = 7.87*10^7 / 6.022*10^23, leading to the conclusion that x = 1.3*10^-16.
6 0
16 days ago
How many lead (Pb) atoms will be generated when 5.38 moles of ammonia react according to the following equation: 3PbO+2NH3→3Pb+N
castortr0y [2808]

Answer:

4.86×10^23 lead molecules

Explanation:

Using the provided equation, 2 moles of ammonia produces 3 moles of lead.

Thus:

2 mol NH3/ 3 mol Pb

By utilizing this proportion, we can calculate the quantities for each molecule. For 5.38 mol NH3:

(5.38 NH3)(3 Pb/ 2 NH3) = (5.38)(3/2) mol Pb = 8.07 mol Pb

Next, we will apply Avogadro's number to determine the total number of molecules.

(8.07)(6.02×10^23) = 4.86×10^23 lead molecules

4 0
11 days ago
Read 2 more answers
Dissolving NaOH(s) in water is exothermic. Two calorimetry experiments are set up. Experiment 1: 2 g of NaOH are dissolved in 10
eduard [2566]

Answer:

a. the temperature changes will be identical

Explanation:

Dissolving sodium hydroxide (NaOH) in water is an exothermic process, with the heat released calculated using:

Q = m×C×ΔT

Where Q indicates the heat released, m refers to the mass of the solution, C is the specific heat, and ΔH stands for temperature change.

The specific heat of both solutions remains the same (because both are the same solutions). Specific heat = C.

m denotes the mass of the solutions: 102g for experiment 1 and 204g for experiment 2.

The heat released, Q: If 2g releases X heat, then 4g releases 2X.

Thus, the temperature change for each experiment is:

Experiment 1:

X / 102C = ΔT

Experiment 2:

2X / 204C = ΔT

X / 102C = ΔT

Indicating that,

a. the temperature changes will be identical

5 0
1 month ago
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