A negative formation enthalpy indicates that the reaction releases heat during the process.
(C,)
Response:
The topmost layer is the Aqueous layer, while benzoic acid resides in the oil phase or non-aqueous layer.
Clarification:
A separating funnel is an essential tool in laboratories, utilized to split the components of immiscible liquid-liquid mixtures. This method is applied during the extraction of mixture components.
The liquids will segregate into two distinct layers. This separation occurs due to the variations in density; the heavier liquid descends to the bottom whereas the lighter liquid floats on top. The liquids involved in such separation are typically dissimilar, with one being the aqueous layer and the other the non-aqueous layer.
The partition coefficient, also known as the distribution coefficient, refers to the ratio of a compound's concentration in two immiscible solvents when in equilibrium.
Organic solvents (with the exception of halogenated organic compounds) that have densities exceeding that of water, 1g/mL (commonly referred to as the oil phase), settle beneath the aqueous layer.
Benzoic acid is found at the lower phase (i.e., the bottom layer).
The partial pressure of nitrogen gas is calculated to be 21.16 MPa.
The partial pressure of oxygen equates to 5.62 MPa, and the overall gas pressure is stated as 26.78 MPa.
This adheres to the principle that the total pressure in a gas system equals the sum of all individual gas partial pressures.
Thus, the total pressure in the system reflects the sum of the partial pressures of nitrogen and oxygen.
Accordingly, the partial pressure for nitrogen can be derived as follows: Total pressure minus the partial pressure of oxygen.
Thus resulting in: 26.78 - 5.62, which gives a partial pressure of nitrogen at 21.16 MPa.
Answer:
78.96 g of NaC2H3O2
Explanation:
The following information is provided:
- The solution's volume is 350 mL
- The solution's molarity is 2.75 M
- The molar mass of NaC2H3O2 is 82.04 g/mol
We need to find the mass of the solute:
First, we calculate the number of moles:
Moles = Molarity × Volume
Thus;
Moles of solute = 2.75 M × 0.350 L
= 0.9625 moles
Next, we find the mass:
Mass = Moles × Molar mass
= 0.9625 moles × 82.04 g/mol
= 78.9635 g
= 78.96 g
Therefore, the amount of NaC2H3O2 required is 78.96 g
(a)
Write the balanced half-reactions for the overall process:
Oxidation: Se^2- (aq) → Se
(s) + 2e-
Reduction: 2So3^2- (aq) + 3H2O (l) + 4e- →
S2O3^2- + 6OH- (aq)
(b)
Assuming E sulfite is 0.57 V, compute E selenium:
E anode = E cathode – E cell
= -0.57 – 0.35
=
-.092
