Answer: C. 151 g
Solution: The balanced equation given is:

From this equation, the ratio of moles between all substances is 1:1. We have 117 grams of LIOH and 141 grams of HBr available and need to calculate the theoretical yield of LiBr.
We should convert each reactant’s grams into moles to identify the limiting reagent since the theoretical yield relies on it.
Molar mass for LiOH = 6.94 + 15.999 + 1.008 = 23.947 grams per mole
Molar mass for HBr = 1.008 + 79.904 = 80.912 grams per mole
To find the moles of each reactant, we divide their grams by their respective molar masses.
Moles of LiOH =
= 4.89 mol
Moles of HBr =
= 1.74 mol
As there are fewer moles of HBr, it is the limiting reactant. With a 1:1 mol ratio between HBr and LiBr, 1.74 moles of LiBr can be produced.
Molar mass of LiBr = 6.94 + 79.904 = 86.844 grams per mole
The mass of LiBr formed =
= 151 g LiBr
Based on calculations, the theoretical yield of LiBr is 151 g, hence the correct answer is C.