camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Usin
1 answer:
The question lacks details. Here is the full question.
The accompanying image was captured with a camera capable of shooting between one and two frames per second. A series of photos was merged into this single image, meaning the vehicles depicted are actually the same car, documented at different intervals.
Assuming the camera produced 1.3 frames per second for this image and that the length of the car is approximately 5.3 meters, based on this information and the photo, how fast was the car moving?
Answer: v = 6.5 m/s
Explanation: The problem requires calculating the car's velocity. Velocity can be computed using:
Since the camera captured 7 images of the car and its length is noted as 5.3, the car's displacement is:
Δx = 7(5.3)
Δx = 37.1 m
The camera operates at 1.3 frames per second and recorded 7 images, thus the time driven by the car is:
1.3 frames = 1 s
7 frames = Δt
Δt = 5.4 s
<pconsequently the="" car="" was="" driving="" at:="">v = 6.87 m/s
<pthe car="" moved="" at="" an="" estimated="">velocity of 6.87 m/s.
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Answer:
Maximum emf = 5.32 V
Explanation:
Provided data includes:
Number of turns, N = 10
Radius of loop, r = 3 cm = 0.03 m
It made 60 revolutions each second
Magnetic field, B = 0.5 T
We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:
For the maximum emf,
Therefore,
Hence, the maximum emf generated in the loop is 5.32 V.
Answer:
1.43 x 10¹⁷.
They will move away from each other.
Explanation:
The force acting on each charged sphere is determined as F = mass x acceleration
= 8.55 x 10⁻³ x 25 x 9.8
= 2.095 N
Assuming Q is the charge on each sphere
F =
Using the values, 2.095 =
We find that Q² =
Thus, Q = 2.289 X 10⁻⁶
The quantity of electrons = Charge / charge of a single electron
=
=1.43 x 10¹³.
They will accelerate away from each other.
Answer:
At this position, the magnetic field equals ZERO
Explanation:
The magnetic field produced by a moving charge is described as
Here, we determine the direction of the magnetic field using
Thus, we find
Leading to a magnetic field of ZERO
Consequently, when the charge moves in the same line as the given position vector, the magnetic field will be nonexistent