camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Usin

Utiliza Scoratic, funciona con cualquier tema.

V = Volume of gas sample = 1.00 L = 0.001 m³T = temperature of gas = 25.0 °C = 25 + 273 = 298 K P = pressure = 1.00 atm = 101325 Pa n = number of moles of gas using ideal gas law:PV = n RT101325 (0.001) = n (8.314) (298)n = 0.041 n₁ = moles of heliumn₂ = moles of neonm₁ = mass of helium = n₁ (4) = 4 n₁m₂ = mass of neon = n₂ (20.2) = 20.2 n₂given that:m₁ = m₂4 n₁ = 20.2 n₂n₁ = 5.05 n₂also n₁ + n₂ = n5.05 n₂ + n₂ = 0.041n₂ = 0.0068mole fraction of neon is mole fraction = n₂ /n = 0.0068/0.041 = 0.166P₂ = partial pressure of neon =(mole fraction) P P₂ = (0.166) (1)P₂ = 0.166 atm

Answer:

Explanation:

An image of the bond resulting from the search is attached.

Consider the force directed towards thymine as negative.

For the O-H-N combination:

The resulting force from this combination is:

In the case of the N-H-N combination:

The total force acting from this combination is:

The force that thymine applies on adenine is:

When rounded to three significant figures, the net force is

b)

The negative value indicates that the force is attractive, as it is aimed towards thymi.

c)

The force acting on the electron due to the proton is:

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.

d)

The ratio of the above forces is:

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.

The equation U = Q + W defines the internal energy of the system, where U represents internal energy, Q corresponds to heat, and W is work done. You have an input of 2,380 J for work alongside 12,900 J of heat, which totals 15,280 J for internal energy.

Answer:

 = 3289.8 m/s

Explanation:

This problem can be approached using momentum definitions.

     I = ∫ F dt

We substitute and compute.

     I = ∫ (at - bt²) dt

Integrating gives us:

      I = a t² / 2 - b t³ / 3

We will evaluate between the limits I=0 for t = 0 ms and higher I=I for t = 2.74 ms:

      I = a (2.74² / 2- 0) - b (2.74³ / 3 -0)

      I = a 3.754 - b 6.857

Substituting the values for a and b, we find:

      I = 1500 3.754 - 20 6.857

      I = 5,631 - 137.14

      I = 5493.9 N s

Next, we engage the relationship between impulse and momentum:

      I = Δp = m - m v₀o

      I = m - 0

       = I / m

     = 5493.9 /1.67

     = 3289.8 m/s