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lesya692
16 days ago
12

The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (

Note: 1 kg = 1000 g).
Physics
1 answer:
Keith_Richards [1K]16 days ago
6 0

Answer:

Momentum is expressed as p = 7.2 g-m/s

Explanation:

It is given that,

The momentum of the object is p=7.2\times 10^{-3}\ kg-m/s

We need to represent momentum in alternative equivalent units. There are various solutions to this issue. For instance, mass units can be represented in grams, milligrams, etc., and length can be in meters, millimeters, etc.

Since, 1 kg = 1000 grams

Thus, p=7.2\times 10^{-3}\times 10^3\ g-m/s

Therefore, the momentum of the object is 7.2 g-m/s. This is the solution needed.

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To address this scenario, we apply the principle of momentum conservation. Given that momentum equals mass multiplied by velocity, we have:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ represent the initial velocities of carts A and B,
v₁' and v₂' denote the final velocities of the respective carts,
and m₁ and m₂ are their masses.

(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁', we find that
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7 0
6 days ago
The thrust of a certain boat’s engine generates a power of 10kW as the boat moves at constant speed 10ms through the water of a
ValentinkaMS [1149]

Answer:

The power increase is 4400 W.

Explanation:

Given data,

Power = 10 kW

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New speed = 12 m/s

The relevant equation is:

F=kv

It's known that,

The expression for power is,

P=Fv

Substituting the value of F into the formula gives

P=(kv)v

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Now we must determine the new power

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\dfrac{P}{P'}=\dfrac{v^2}{v'^2}

Insert the value into the equation

\dfrac{10}{P'}=(\dfrac{10}{12})^2

P'=(\dfrac{12}{10})^2\times10

P'=14.4\ kW

Next, we calculate the change in power

Using the formula for power change

\Delta P=P'-P

Insert values into the equation

\Delta P=14.4-10

\Delta P=4.4\ kW

\Delta P=4.4\times1000

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9 days ago
Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used
ValentinkaMS [1149]

Answer:

w= 1.867\times10^{-2}

Explanation:

Provided:

fiber diameter d= 18 μm

screen distance D= 30 cm

wavelength λ= 560 nm

from this, we can determine the fringe width

w=\frac{2\lambda D}{d}

substituting the values yield

w=\frac{2\times560\times10^{-9}\times0.3}{18\times10^{-6}

w= 1.867\times10^{-2}

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4 days ago
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6 0
2 days ago
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A mechanical high-speed bat is flying along a path perpendicular to a wall. it emits a sound with a frequency f0 . the night is
inna [987]
1. f1 = Vs + Vbat Vs fO
2. f1 = Vs Vs - Vbat fO
3. f1 = Vs Vs + Vbat fO
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5. f1 = 2Vs Vs - Vbat fO
6. f1 = Vs - Vbat Vs fO
7. f1 = Vs - Vbat Vs + Vbat fO
8. f1 = fO
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The frequency that is detected is
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