Answer:
v = 54.2 m/s
Explanation:
We can utilize conservation of energy to solve this issue.
Initial condition Higher
Em₀ = U = m g h
Final condition. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ (2gh)
Now let's perform the calculation
v = √ (2 * 9.8 * 150)
v = 54.2 m/s
The final calculated height is 22.2 km. By converting 3397 km to meters, we achieve 3397000m. Using the gravitational constant, we compute the gravitational acceleration on the planet in accordance with Newton's law of gravitation, where M and R represent the planet's mass and radius, respectively. As the bullet ascends to its peak height, its kinetic energy transitions to potential energy. We account for the bullet mass and its initial velocity of 406 m/s, simplifying both sides of the equation to ultimately express the height reached as 22.2 km.
Answer:
The accurate statements are
2. The train is not an inertial frame of reference.
5. The train could be moving at a constant velocity in a circular path.
8. The train must be undergoing acceleration.
Explanation:
As we observe that the string forms an angle with the horizontal
we can formulate the force equation relevant to the given ball
similarly in the Y direction
Thus we conclude
This leads us to deduce that the train is accelerating with an acceleration identical to that of gravity
The correct statements will be
2. The train is not an inertial frame of reference.
5. The train could be moving at a constant speed in a circular path.
8. The train must be experiencing acceleration.
Example Response: The technology referenced is fiber optics. Their small size and flexibility allow doctors to visualize areas that would otherwise require surgical intervention to examine.
Answer:
1 angstrom equals 0.1 nm.
To convert 5000 angstroms: 5000 angstrom = 5000 / 1 × 0.1 nm.
= 500 nm
To express 5000 angstroms in meters: 5000 angstrom = 5000 × 1 × 10^-10.
= 5 × 10^-7 m
Hope this explanation is useful for you.
