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mestny
1 month ago
9

Which of the following is (are) true of ligand-gated ion channels?

Physics
1 answer:
Ostrovityanka [3.2K]1 month ago
3 0

Answer:

The properties of ligand-gated ion channels include:

a. They play a crucial role in the nervous system by altering sodium and calcium levels within cells.  

b. Their significance is primarily linked to the nervous system.

c. They are vital for the nervous system, responsible for modulating sodium and calcium levels in cells, and they respond to chemical signals by either opening or closing.

Explanation:

Ligand-gated ion channels (LICs or LGICs), often called ionotropic receptors, represent a class of trans-membrane ion-channel proteins that open to permit the flow of ions like Na+, K+, Ca2+, and/or Cl− across membranes in reaction to the binding of chemical signals. Their function contrasts with that of voltage-gated ion channels, which are triggered by changes in voltage across membranes (i.e., when depolarization occurs) and are responsive to membrane potentials. In comparison to GPCRs that utilize secondary messengers, ligand-gated channels operate upon the binding of a ligand (a specific chemical signal). Both types of channels are essential for the effective activation of the post-synaptic neuron.

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6 0
1 month ago
"A block of metal weighs 40 N in air and 30 N in water. What is the buoyant force on the block due to the water? The density of
Sav [3153]

Answer:

The buoyant force acting on the block from the water is 10 N

Explanation:

The buoyant force (F_B) experienced by a block is defined as the difference between its actual weight in air and its weight when submerged in water.

The data provided indicates:

A metal block weighs 40 N in air and 30 N in water.

Thus, F_B = 40 - 30 = 10 N

therefore,  the buoyant force acting on the block from the water amounts to 10 N

6 0
1 month ago
Read 2 more answers
A wire, of length L = 3.8 mm, on a circuit board carries a current of I = 2.54 μA in the j direction. A nearby circuit element g
Keith_Richards [3271]

It equals 5z

Explanation:

5z

5 0
1 month ago
How would the interference pattern change for this experiment if a. the grating was moved twice as far from the screen and b. th
Softa [3030]

Answer:

Refer to the explanation

Explanation:

Solution:-

- For this problem, we will assume the grating has a defined line density ( N ) representing the lines per mm.

- The angle formed by each fringe on the screen is given by ( θ ).

- The order of bright/dark spots is characterized by an integer ( n )

- The incident light's wavelength is ( λ )

- Using the diffraction grating relationship from the Young's Experiment is as follows:

                               n*lambda = \frac{sin(theta)}{N}

- The provided formula corresponds to constructive interference.

- We will examine how increasing the distance between the screen and the grating affects the pattern. Let ( L ) be the distance from the grating center to the screen center. The distance ( yn ) indicates the vertical spacing between each fringe on the screen.

- For small angles ( θ ), we use the approximation of sin ( θ ) ≈ tan ( θ ). Thus,

                            sin ( θ ) ≈ tan ( θ ) = [ yn / L ]

- Replacing this approximation in the diffraction grating relation results in:

                            y_n = n*lamda*L*N

- To double the distance from the screen to the grating, we use the relation with ( 2L ):

                            yn ∝ L

Result: The separation between each order of bright and dark fringe doubles. The interference pattern will spread further! Consequently, there will be fewer bright spots visible on the screen since a larger surface area is required to accommodate the entire pattern. The increased distance also diminishes the intensity contrast between bright and dark fringes due to the extended path traveled by light rays. Intensity is inversely related to the square of the travel distance.

- If the line density of the grating ( N ) were doubled, it follows that:

                            yn ∝ N

Result: The spacing between bright and dark fringes would also double. The interference pattern expands further, leading to the necessity of a bigger screen to show the entire pattern.

4 0
1 month ago
A motorcycle traveling at 36 m/s slams on the brakes to avoid an accident. The motorcycle skids 23m before stoping. What is the
ValentinkaMS [3465]
Since the motorcycle was at a speed of 36 m/s prior to braking, that marks the initial velocity.
u = 36 {ms}^{ - 1}
The motorcycle skidded 23m before coming to a full stop, indicating that
s = 23m
As it has ceased motion, the final velocity is zero.

v = 0{ms}^{ - 1}
We can apply the 'suvat' formula relevant to linear motion.

{v}^{2} = {u}^{2} + 2as
Substituting the aforementioned values allows us to find,

{0}^{2} = {36}^{2} + 2a(23)


0 = 1296+ 46a
46a = - 1296
a = - 28.2 {ms}^{ - 2}


We can apply the formula
v = u + at
to calculate the time required for the motorcycle to stop.

0 = 36 + - 28.2t
- 36 = - 28.2t
t = 1.3s
8 0
2 months ago
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