Before any forces are applied, all cars maintain a constant speed of 2 m/s. Following that, the ranking is as follows:
1. Best: 6th car; Fr = 10 N,
2. 1st car ; Fr = 2.95 N.
3. Next: 2nd, 3rd and 5th car ; Fr = 0 N
4. Least: 4th car ; Fr = -2.04 N.
Answer:
The result is 0.750 NC
Explanation:
I am also taking the same test
Answer:
The force will rise in direct relation to the mass of the objects
Explanation:
The gravitational acceleration remains constant. It is measured in meters per second squared or m/s². The average value is 9.81 m/s², calculated from observations made on varying surfaces. In reality, the acceleration can vary based on the geographical shape of the Earth relative to the earth's magnetic field and gravitational force.
For instance, if a single washer weighs 20 kg, with the gravity at 9.81 m/s², the weight would be:
F = ma
= 
If there are three washers, the total weight calculates as:
F = 3 * 20 * 9.81
= 588.6 N
Answer:
ΔL = MmRgt / (2m + M)
Explanation:
The system starts from rest, so the change in angular momentum correlates directly to its final angular momentum.
ΔL = L − L₀
ΔL = Iω − 0
ΔL = ½ MR²ω
To determine the angular velocity ω, begin by drawing a free body diagram for both the pulley and the block.
For the block, two forces act: the weight force mg downward and tension force T upward.
For the pulley, three forces are present: weight force Mg down, a reaction force up, and tension force T downward.
For the sum of forces in the -y direction on the block:
∑F = ma
mg − T = ma
T = mg − ma
For the sum of torques on the pulley:
∑τ = Iα
TR = (½ MR²) (a/R)
T = ½ Ma
Substituting gives:
mg − ma = ½ Ma
2mg − 2ma = Ma
2mg = (2m + M) a
a = 2mg / (2m + M)
The angular acceleration of the pulley is:
αR = 2mg / (2m + M)
α = 2mg / (R (2m + M))
Finally, the angular velocity after time t is:
ω = αt + ω₀
ω = 2mg / (R (2m + M)) t + 0
ω = 2mgt / (R (2m + M))
Substituting into the previous equations gives:
ΔL = ½ MR² × 2mgt / (R (2m + M))
ΔL = MmRgt / (2m + M)
