In very cold weather, a significant mechanism for heat loss by the human body is energy expended in warming the air taken into t

Answer:

C) True. The distance S increases over time, with v₁ = gt and v₂ = g (t-t₀), illustrating that v₁> v₂ for the same t.

Explanation:

We have a set of statements to evaluate for correctness. The most effective approach is to examine the problem in detail.

Using the equation for vertical launch, we acknowledge that the positive direction signifies downward movement.

Stone 1

    y₁ = v₀₁ t + ½ g t²

    y₁ = 0 + ½ g t²

Stone 2

Released shortly thereafter, let's assume a delay of one second, we can utilize the same timing mechanism

     t ’= (t-t₀)

    y₂ = v₀₂ t ’+ ½ g t’²

    y₂ = 0 + ½ g (t-t₀)²

    y₂ = + ½ g (t-t₀)²

We can now calculate the separation distance between the two stones, which is applicable for t> = to

    S = y₁ -y₂

    S = ½ g t²– ½ g (t-t₀)²

    S = ½ g [t² - (t² - 2 t t₀ + t₀²)]  

    S = ½ g (2 t t₀ - t₀²)

    S = ½ g t₀ (2 t - t₀)

This represents the distance between the two stones over time, with the coefficient outside the parentheses being constant.

For t < to, the first stone remains stationary while the distance grows.

For t > = to, the expression (2t/to-1) yields a value greater than 1, indicating that the distance expands as time progresses.

We can now analyze the different statements

A) false. The height difference increases over time.

B) False S increases.

C) It is true that S increases over time, with v₁ = gt and V₂ = g (t-t₀) indicating v₁> v₂ at the same t.

Answer:

Cl2 concentration: 1,048 ppm

Explanation:

Molarity (M) is a unit that indicates how many moles of a substance are in one liter of solution, while ppm is similar to mg/L, representing the mass of the substance per liter. To convert M to ppm, we need to consider both mass and volume. The volume remains in liters in both cases, so no adjustments are needed there. The challenge arises when converting moles from molarity to milligrams for the mg/L conversion to find ppm.

First, we must recognize that the substance in question is Cl2, prompting the need to connect mole quantity to its mass. Referring to the periodic table, we find the atomic weight of Cl is 35.4 g/mole. This relationship allows us to establish moles' mass, as shown in the following equation:

We already know the moles of Cl2 in the solution is (moles=2.96x10^-5). Substituting this value, we can calculate:

Keep in mind that we're discussing the mass found per liter of solution, which gives us 1.048x10^-3 g/L. We previously established that ppm equals mg/L, so we need to convert grams to milligrams:

1 g = 1000 mg

Now multiplying both sides by 1.048x10^-3:

1 * 1.048x10^-3 g = 1000 * 1.048x10^-3 mg

Thus, 1,048x10^-3 g translates to 1,048 mg.

This amount of mass detected in one liter indicates that the concentration of the substance in the solution is:

1,048 mg/L

Since we know that mg/L=ppm, the conclusion is:

1,048 ppm

Respuesta:

P_(bomba) = 98,000 Pa

Explicación:

Se nos proporciona;

h2 = 30m

h1 = 20m

Densidad; ρ = 1000 kg/m³

Primero, entendemos que la suma de las presiones en el tanque y la bomba es igual a la del boquilla,

Así, se puede expresar como;

P_(tanque)+ P_(bomba) = P_(boquilla)

Ahora, la presión se daría como;

P = ρgh

Y así,

ρgh_1 + P_(bomba) = ρgh_2

P_(bomba) = ρg(h_2 - h_1)

P_(bomba) = 1000•9.8(30 - 20)

P_(bomba) = 98,000 Pa