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1 month ago

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you are sitting on a beach and a wave strikes the shore every 10 seconds. a surfer tells you that these waves travel at a speed

of 5m/is. how far apart are the crests of the waves , i.e what is the wavelength of these water waves? give your answer in meters.

1 answer:

ValentinkaMS [3.4K]1 month ago

5 0

Answer:

50 meters

Explanation:

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A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0. Wha

serg [3582]

Answer:

$a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}$

Explanation:

Data provided

initial velocity v₀=20 cm/s at time t=3s

final velocity vf=0 at time t=8 s

Required

Average Acceleration for the interval from 3s to 8s

Solution

Acceleration can be defined as the first derivative of velocity concerning time

$a_{acceleriation} =\frac{dv_{velocity}}{dt_{time}}\\a_{acceleriation} =\frac{v_{f}-v_{o} }{dt}\\ a_{acceleriation} =\frac{0-20cm/s }{8s-3s}\\ a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}$

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1 month ago

A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum e

kicyunya [3294]

Answer:

Maximum emf = 5.32 V

Explanation:

Provided data includes:

Number of turns, N = 10

Radius of loop, r = 3 cm = 0.03 m

It made 60 revolutions each second

Magnetic field, B = 0.5 T

We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:

$\epsilon=\dfrac{d(NBA\cos\theta)}{dt}\\\\\epsilon=NBA\dfrac{d(\cos\theta)}{dt}\\\\\epsilon=NBA\omega \sin\omega t\\\\\epsilon=NB\pi r^2\omega \sin\omega t$

For the maximum emf, $\sin\omega t=1$

Therefore,

$\epsilon=NB\pi r^2\omega \\\\\epsilon=NB\pi r^2\times 2\pi f\\\\\epsilon=10\times 0.5\times \pi (0.03)^2\times 2\pi \times 60\\\\\epsilon=5.32\ V$

Hence, the maximum emf generated in the loop is 5.32 V.

3 0

2 months ago

A rare and valuable antique chest is being moved into a truck using a 4.00 m long ramp. the kj weight of the chest plus packing

ValentinkaMS [3465]

We start by finding the angle of inclination with the sine function,

sin θ = 1 m / 4 m

θ = 14.48°

Next, we compute the work done by the movers using the following formula:

W = Fnet * d

We need to first determine Fnet. It is the weight force minus the frictional force.

Fnet = m g sinθ – μ m g cosθ

Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48

Fnet = 84.526 N

The work done is therefore:

W = 84.526 N * 4 m

<span>W = 338.10 J</span>

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1 month ago

Two events are observed in a frame of reference S to occur at the same space point, with the second event occurring after a time

Sav [3153]

Answer:

The distinction between the locations of the two events as perceived in S is calculated to be 4.42 x 10^8 m

Explanation:

The time dilation concept has been utilized to address this question, as detailed in the attachment.

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29 days ago

In the ENGR 10 lab (E391), there are 50 long light bulbs (P=100 W) and 30 regular bulbs (P=60 W). How much energy is consumed li

Ostrovityanka [3204]

Answer:

The total energy saving achieved will be 0.8 KWH

Explanation:

It is provided that there are 50 long light bulbs rated at 100 W, thus the total power consumed by 50 bulbs equals 100×50 = 5000 W = 5 KW

Additionally, 30 bulbs are rated at 60 W

Consequently, the total power consumption of 30 bulbs is 30×60 = 1800 W = 1.8 KW

The cumulative power of all 80 bulbs is 1.8 + 5 = 6.8 KW

Considering the operation time of 3 hours

We know that energy $E=power\times time=6.8\times 3=20.4KWH$

Now, the power consumption per CFL bulb equals 25 W

Thus for 80 bulbs, power equals 80×25 = 2000 W = 2 KW

So the energy for 80 bulbs amounts to 2×3 = 6 KWH

Hence, the overall energy saving is 6.8 - 6 = 0.8 KWH

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1 month ago