To address this issue, we will utilize the principles related to Gauss' law, which states that the electric flux across a surface corresponds to the object's charge divided by the permittivity of vacuum. In mathematical terms, this can be expressed as
It's crucial to remember that the net charge equals the difference between the two specified charges, so upon substitution,
The negative sign indicates that the flux is directed into the surface
Answer:
The number of photons emitted each second is
Explanation:
Let 'n' stand for the quantity of photons released by the bulb.
Provided Information:
The bulb radiates energy at a rate of 100 J per second (E).
Wavelength of emitted light is (λ) = 525 nm =
The energy of a photon is calculated by:
Where,
Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,
To express in terms of 'n', we find:
Insert the provided values and solve for 'n'. The resulting calculation yields
Consequently,
photons are discharged every second.
The height from which the drops fall is 3.57m
Assuming the drops fall at a rate of 1 drop every t seconds. The initial drop takes 5t seconds to hit the ground. The second drop reaches the bottom of the 1.00 m window in 4t seconds, while the third drop reaches the top of the window in 3t seconds.
Calculate the distances covered by the second and third drops s₂ and s₃, which begin from rest at the building's roof.
The height of the window s is described by,
The first drop has reached the base after taking 5t seconds.
The roof height h represents the distance covered by the first drop and is expressed as,
the height of the roof remains at 3.57 m
