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Komok
5 days ago
6

A cart moves along a track at a velocity of 3.5 cm/s. When a force is applied to the cart, its velocity increases to 8.2 cm/s. I

f it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? Round your answer to the nearest tenth. cm/s2
Physics
2 answers:
serg [1.1K]5 days ago
5 0
First, we need to establish the motion equations for the cart.
This leads us to:
vf = a * t + vo
By substituting the values, we have:
8.2 = a * (1.5) + (3.5)
Solving for acceleration gives:
 a = (8.2-3.5) / (1.5)
 a = 3.1 m / s ^ 2
Response:
The acceleration of the cart is:
a = 3.1 m / s ^ 2
serg [1.1K]5 days ago
5 0

Answer:

3.1 cm/s²

Explanation:

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