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2 days ago

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A distance of 2.00 mm separates two objects of equal mass. If the gravitational force between them is 0.0104 N, find the mass of

each object

2 answers:

inna [2.2K]2 days ago

4 0

The mass of each object is 24.97 Kg. Distance between masses is given as d = 2 mm = 0.002 m. The gravitational force between the masses is F = 0.0104 N. Assuming m is the mass of both objects, we know the gravitational force can be described by the stated relation. Thus, m = 24.97 Kg. Therefore, each object's mass is 24.97 Kg, which is the sought solution.

Sav [2.2K]2 days ago

4 0

F = $\frac{gm,m2}{r2}$
r = 0.002

0.0104 = $\frac{(6.673 x 10^{-11} }{ 0.002)^{2} }$

m = 25.0kg

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1 month ago

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1 month ago

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Answer:

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Explanation:

Conceptual analysis

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d: distance from the charge q to point P in meters (m)

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d₂ = 5 * 10⁻² m

Part A) Calculation for electric fields at point from q₁ and q₂:

Refer to the attached illustration:

E₁: Electric Field at point P(0,4) cm due to charge q₁. Since q₁ is negative (q₁-), the electric field approaches the charge.

E₂: Electric Field at point P(0,4) cm due to charge q₂. Since q₂ is positive (q₂+), the electric field emanates from the charge.

E₁ = k*q₁/d₁² = 9 * 10⁹ * 6 * 10⁻⁹ / (4 * 10⁻²)² = 33.75 * 10³ N/C

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E₂ = (6.48 (-i) + 8.64 (+j)) * 10³ N/C

Part B) Calculation for net electric field at P (Ep)

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Ep = (6.48 * 10³ (-i) + 25.11 * 10³ (-j)) N/C

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3 0

14 days ago

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Answer:

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$\Delta v\geq\frac{5.78*10^{-5}}{50*10^{-9}m}=1157.08\frac{m}{s}$

If we treat the electron like a classic particle, the time required to cross the channel is determined using the upper limit of the uncertainty in velocity:

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