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1 month ago

How did Newton use creativity and logic in his approach to investigating light?

2 answers:

8 0

Isaac Newton displayed creativity by employing prisms to demonstrate that white light comprises various colors. He utilized logic in the rhetorical structure of his arguments to persuade his audience of his conclusions' validity.

He was not the initial experimenter with prisms; French philosopher Rene Descartes had conducted similar experiments. However, Descartes believed that the prism altered the light to create the color spectrum. Newton, on the other hand, accurately recognized that light refracting through a prism exposes the inherent colors within it. He utilized a second prism, filtering out all but one color, to illustrate that a lone color did not change when passing through a prism. By adjusting this second prism, he also proved that the various colors of light could be blended back into white light. Newton's 1672 paper on light refraction through prisms solidified his standing as a scientist, and he continued to explore light throughout his career, publishing a more extensive work in 1704 on Opticks (as optics was spelled at the time).

Sav [3.1K]1 month ago

3 0

He approached the concept of light using quantum mechanics to explain relativity and perspective.

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You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball

Softa [3030]

Explanation:

The amount of work performed corresponds to the variation in energy.

W = ΔKE

W = 0 − ½mv²

W = -½ (0.270 kg) (-7.50 m/s)²

W = -7.59 J

Work can be defined as the product of force and distance.

W = Fd

-7.59 J = F (-0.150 m)

F = 50.6 N

3 0

1 month ago

A convex mirror with a focal length of 0.25 m forms a 0.080 m tall image of an automobile at a distance of 0.24 m behind the mir

ValentinkaMS [3465]

Answer:

The object measures 6 m in distance and 2 m in height.

It creates a virtual image that is upright.

Explanation:

Provided data includes:

Focal length = 0.25 m

Image height = 0.080 m

Image distance = 0.24 m

We are to determine the object's distance.

Using the lens formula:

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}$

Substituting values into the formula:

$\dfrac{1}{0.24}=\dfrac{1}{0.25}+\dfrac{1}{u}$

$\dfrac{1}{u}=\dfrac{1}{0.24}-\dfrac{1}{0.25}$

$\dfrac{1}{u}=\dfrac{1}{6}$

$u=6\ m$

We also need to calculate magnification:

Applying the magnification formula:

$m=-\dfrac{v}{u}$

Substituting values into this formula:

$m=-\dfrac{0.24}{-6}$

$m=0.04$

Next, we need to find the height of the object:

Using the magnification formula once more:

$m=\dfrac{h'}{h}$

$h=\dfrac{0.080}{0.04}$

$h=2\ m$

A convex mirror generates a virtual and upright image on its backside.

Consequently, the object is at a distance of 6 m and has a height of 2 m.

The image formed is virtual and upright.

6 0

2 months ago

Read 2 more answers

A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i

inna [3103]

In physics, acceleration describes how an object's velocity changes over time. Whenever the speed of an object shifts, it's considered to be accelerating. To calculate acceleration here:

acceleration = (8.2 - 3.5) / 1.5 = 3.1 m/s²

I trust this answers your question.

5 0

2 months ago

Read 2 more answers

Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used

ValentinkaMS [3465]

Answer:

$w= 1.867\times10^{-2}$