Some oxygen gas takes up a volume of 2.00 liters at 0.99 atm and 273 K. Its volume doubles and its temperature decreases to 137

Givens

• V1 = 5.00 L
• V2 =?
• T1 = 298 K
• T2 = 333 K

Formula

V1/T1 = V2/T2

Note: This will be applicable only if the pressure remains constant.

Solution

5.00L / 298 K = x / 333 K. Multiply both sides by 333 K.

5.00 * 333 / 298 = x 333/ 333

V2 = 5.59 L

 

Response: 1-methoxy-2,4-dinitrobenzene

Rationale:

The nitro groups exhibit a strong electron-withdrawing effect, facilitating nucleophilic substitution reactions where a substituent is replaced by a robust nucleophile like the methoxy group. The reaction's mechanism is illustrated below. The electron-withdrawing nature of the nitro group aids in the formation of the intermediate during the reaction as depicted.

CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O

m(CO₂)/{xM(CO₂)}=m(H₂O)/{0.5yM(H₂O)}

0.2845/{44.01x}=0.1451/{9.01y}

x/y=0.4=2:5

The empirical formula is C₂H₅.

Hello, in this situation, the chemical reaction occurring is as follows: Next, we will ascertain the limiting reactant by calculating the moles of magnesium oxide produced from 3.86 g of magnesium and 155 mL of oxygen using the given mole ratios of 2:1:2 and applying the ideal gas equation, demonstrating that oxygen is the limiting reactant because it generates the least magnesium oxide. Subsequently, we determine the mass of magnesium consumed solely by the oxygen.

Response: Water molecules migrate from the dilute to the concentrated solution

Clarification:

During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.

Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.