For this issue, the answer is clarified as the system takes in energy (+). The surroundings contribute 84 KJ of work. Whenever a system is receiving work from its surroundings, the value will be positive. Therefore, it sums to 12.4 KJ + 4.2 = 16.6 KJ.
Answer:
v = 66.4 m/s
Explanation:
We know that the aircraft starts off moving at a speed of

now we have




in the Y direction, we can apply kinematic equations



as there is no acceleration along the x-axis, the velocity in this direction remains unchanged
thus yielding



The question pertains to the change in frequency of a wave noted by an observer moving in relation to the source, indicating that the concept to invoke is "
Doppler's effect."
The standard formula for the Doppler effect is:

-- (A)
Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.
Where,
g = Speed of sound = 340m/s.

= Velocity of the observer relative to the medium =?.

= Velocity of the source in relation to the medium = 0 m/s.

= Frequency emitted from the source = 400 Hz.

= Frequency recognized by the observer = 408 Hz.
Substituting the given values into equation (A) will yield:


Solving the above will result in,

= 6.8 m/s
The correct result = 6.8m/s
Applying the formula of force equals mass times acceleration, and considering acceleration approximated as g at 10 m/s², the brick possessing the greater mass will hit the ground first due to its superior force that counteracts resistive forces like air resistance.