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galina1969
3 months ago
7

Problem: An ice hockey player hits a puck of mass 0.15 kilograms with a force of 100 newtons in the horizontal direction. What i

s the acceleration produced by the force in the horizontal direction? Part A: Enter the variable symbol of the quantity you need to solve for. Use your keyboard and the keypad to enter your answer. Then click Done.
Physics
2 answers:
ValentinkaMS [3.4K]3 months ago
7 0
The acceleration of an object will always align with the direction of the resultant force acting upon it. Thus, we can find horizontal acceleration by examining the horizontal force applied, applying Newton's second law in its mathematical form: Force = mass * acceleration. Therefore, acceleration = force / mass. By inputting the numbers, we have a = 100 / 0.15, which results in a = 666.7 m/s². Consequently, the acceleration experienced by the hockey puck is 670 m/s².
serg [3.5K]3 months ago
3 0
For part A, the variable symbol you should enter is x for all my plato users. In part B, it would be F with a little x = ma with a little x. Part C would have a with a little x = F with a little x divided by m. Finally, part D would be a little x = 100 divided by 0.15.
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The δe of a system that releases 12.4 j of heat and does 4.2 j of work on the surroundings is __________ j.
Yuliya22 [3333]

For this issue, the answer is clarified as the system takes in energy (+). The surroundings contribute 84 KJ of work. Whenever a system is receiving work from its surroundings, the value will be positive. Therefore, it sums to 12.4 KJ + 4.2 = 16.6 KJ.

5 0
3 months ago
A plane flying at 70.0 m/s suddenly stalls. If the acceleration during the stall is 9.8 m/s2 directly downward, the stall lasts
ValentinkaMS [3465]

Answer:

v = 66.4 m/s

Explanation:

We know that the aircraft starts off moving at a speed of

v = 70 m/s

now we have

v_x = 70 cos25

v_x = 63.44 m/s

v_y = 70 sin25

v_y = 29.6 m/s

in the Y direction, we can apply kinematic equations

v_y = v_i + at

v_y = 29.6 - (9.81 \times 5)

v_y = -19.5 m/s

as there is no acceleration along the x-axis, the velocity in this direction remains unchanged

thus yielding

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{63.44^2 + 19.5^2}

v = 66.4 m/s

4 0
3 months ago
A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 hz. the sound he hears reflected back from t
Softa [3030]
The question pertains to the change in frequency of a wave noted by an observer moving in relation to the source, indicating that the concept to invoke is "Doppler's effect."

The standard formula for the Doppler effect is:
f = (\frac{g + v_{r}}{g + v_{s}})f_{o} -- (A)

Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.

Where,
g = Speed of sound = 340m/s.
v_{r} = Velocity of the observer relative to the medium =?.
v_{s} = Velocity of the source in relation to the medium = 0 m/s.
f_{o} =  Frequency emitted from the source = 400 Hz.
f = Frequency recognized by the observer = 408 Hz.

Substituting the given values into equation (A) will yield:

408 = ( \frac{340 + v_{r}}{340 + 0})*400

\frac{408}{400} = \frac{340 + v_{r}}{340}

Solving the above will result in,
v_{r} = 6.8 m/s

The correct result = 6.8m/s



7 0
3 months ago
If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
Keith_Richards [3271]

Answer:

2 m/s²

Explanation:

8 0
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