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galina1969
3 months ago
7

Problem: An ice hockey player hits a puck of mass 0.15 kilograms with a force of 100 newtons in the horizontal direction. What i

s the acceleration produced by the force in the horizontal direction? Part A: Enter the variable symbol of the quantity you need to solve for. Use your keyboard and the keypad to enter your answer. Then click Done.
Physics
2 answers:
ValentinkaMS [3.4K]3 months ago
7 0
The acceleration of an object will always align with the direction of the resultant force acting upon it. Thus, we can find horizontal acceleration by examining the horizontal force applied, applying Newton's second law in its mathematical form: Force = mass * acceleration. Therefore, acceleration = force / mass. By inputting the numbers, we have a = 100 / 0.15, which results in a = 666.7 m/s². Consequently, the acceleration experienced by the hockey puck is 670 m/s².
serg [3.5K]3 months ago
3 0
For part A, the variable symbol you should enter is x for all my plato users. In part B, it would be F with a little x = ma with a little x. Part C would have a with a little x = F with a little x divided by m. Finally, part D would be a little x = 100 divided by 0.15.
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Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart
Keith_Richards [3271]

Answer:F=\frac{(M+m)g}{\mu _s}

Explanation:

Provided:

The trolley, with mass M, is allowed to roll freely without friction.

The coefficient of friction between the trolley and mass m is \mu _s.

A force F is applied to mass m.

The acceleration of the system is

a=\frac{F}{M+m}

The frictional force will counterbalance the weight of the block.

The frictional force is =\mu _sN

N=ma

\mu _sN=mg

\mu _sma=mg

\mu _s=\frac{g}{a}

F=\frac{(M+m)g}{\mu _s}

6 0
3 months ago
Read 2 more answers
In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c
Sav [3153]

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

GDP=\pi } \frac{d^{2} }{4}

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

GDP_{b} =\pi \frac{3^{2} }{4}

Conversely, in darkness, the diameter typically enlarges to 7 mm.

GDP_{b} =\pi \frac{7^{2} }{4}

This indicates an increase in light-gathering capacity.

Increase=\pi \frac{49}{4} -\pi \frac{9}{4} \\Increase=31.4 mm^{2}

Thus, the amount of light the eye can capture is 31.4 mm².

3 0
3 months ago
Astronaut A can cover 10 meters per minute walking with the heavy shovel. What does
Softa [3030]
The astronaut's speed is described in the sentence. The astronaut moves at a rate of 10 meters each minute. To clarify: speed is defined as distance divided by time and is characterized solely by its magnitude, not its direction. Hence, the 10 meters per minute reflects this. We lack information about the astronaut's directional movement. In contrast to speed, velocity incorporates direction as well; for instance, a velocity of 10m/s due west provides a directional context. Consequently, without specified direction, the value indicated is merely speed.
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