A 4.0 g string, 0.36 m long, is under tension. The string produces a 500 Hz tone when it vibrates in the third harmonic. The spe
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Answer:
The horizontal distance d that the ball covers before it lands is 1.72 m.
Explanation:
Given,
Height of ramp
Height of bottom of ramp
Diameter = 0.17 m
We need to determine the horizontal distance d the ball travels before landing.
We need to calculate the time
Using the equation of motion
Next, we can find the ball's velocity
Using the kinetic energy formula
By applying the conservation of energy
Next, we determine the horizontal distance d the ball travels before landing
Using the distance formula
Where. d = distance
t = time
v = velocity
We substitute the values into the formula
Thus, the horizontal distance d that the ball travels before it lands is 1.72 m.
The question lacks details. Here is the full question.
The accompanying image was captured with a camera capable of shooting between one and two frames per second. A series of photos was merged into this single image, meaning the vehicles depicted are actually the same car, documented at different intervals.
Assuming the camera produced 1.3 frames per second for this image and that the length of the car is approximately 5.3 meters, based on this information and the photo, how fast was the car moving?
Answer: v = 6.5 m/s
Explanation: The problem requires calculating the car's velocity. Velocity can be computed using:
Since the camera captured 7 images of the car and its length is noted as 5.3, the car's displacement is:
Δx = 7(5.3)
Δx = 37.1 m
The camera operates at 1.3 frames per second and recorded 7 images, thus the time driven by the car is:
1.3 frames = 1 s
7 frames = Δt
Δt = 5.4 s
<pconsequently the="" car="" was="" driving="" at:="">v = 6.87 m/s
<pthe car="" moved="" at="" an="" estimated="">velocity of 6.87 m/s.