Answer:
The specific heat value for silver is 0.236 J/g-C.
Explanation:
Silver has a mass of 25 grams.
The temperature shifts from 31.5° C to 58.7° C.
The required heat is equivalent to 25 g.
To determine silver's specific heat, the following equation applies:

Where c represents the specific heat of silver.

Thus, the specific heat of silver is 0.236 J/g-C.
Response:1816.6 joules
Clarification:refer to the attached image
(a)
Write the balanced half-reactions for the overall process:
Oxidation: Se^2- (aq) → Se
(s) + 2e-
Reduction: 2So3^2- (aq) + 3H2O (l) + 4e- →
S2O3^2- + 6OH- (aq)
(b)
Assuming E sulfite is 0.57 V, compute E selenium:
E anode = E cathode – E cell
= -0.57 – 0.35
=
-.092
Convert HCl and H2O to moles.
36.0 g of HCl = 0.987 moles HCl
98.0 g of H2O = 5.44 moles H2O
Based on the stoichiometric ratio for HCl,
there are 0.987 moles of H and 0.987 moles of Cl.
For H₂O, according to the stoichiometric ratio, you have 10.88 moles of H and 5.44 moles of O.
Combining them:
11.867 moles H
0.987 moles Cl
5.44 moles O
Revert the moles back to grams, then divide by the total mass and multiply by 100 for the percentage by mass.
11.867 moles H = 11.96 g H
0.987 moles Cl = 34.99 g Cl
5.44 moles O = 87.03 g O
11.96/(36.0+98.0)(100) = 8.93% for H
34.99/(36.0+98.0)(100) = 26.11% for Cl
87.03/(36.0+98.0)(100) = 64.96% for O.
Answer:
A pressure of 137.14 MPa exists 10,000 m beneath the ocean surface.
At this same depth, the density measures 2039 kg/m3.
Explanation:
P0 and ρ0 symbolize the pressure and density at sea level (indicative of atmospheric conditions). With an increase in ocean depth, both pressure and density likewise rise.
The relationship between pressure and density can be expressed as:

By rearranging

This equation allows for computation of P at 10,000 m beneath the ocean's surface:

The density found at a depth of 10,000 m in the ocean is
