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Nonamiya
12 days ago
5

if one solution has 100 times as many hydrogen ions as another solution, what is the difference, in pH units between the two sol

ution?
Chemistry
1 answer:
Anarel [2.5K]12 days ago
3 0
Utilize the principle that pH = log { 1 / [H+] }. Designate x as the hydrogen ion concentration of one solution and 100x for the other. The pH of the solution with hydrogen concentration x is pH1 = log {1 / x}. For the solution with 100x concentration, it is pH2 = log {1 / 100x}. Now, you find pH2 - pH1 = log {1/x} - log {1 / 100x}. By applying the properties of logarithms, you arrive at pH2 - pH1 = log {1/x} - log {1/x} - log {1/100} = - (-2) = 2. Thus, the conclusion is that if one solution contains 100 times more hydrogen ions than another, the difference in pH units between the two solutions is 2<span>.</span>
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Answer:

The rate law for the decomposition reaction is:

R=k[D]^2

The unit for the rate constant will be M^{-1}s^{-1}

Explanation:

D\rightarrow Product

The rate law can be expressed as:

R=k[D]^x..[1]

When the drug concentration is tripled, the decomposition rate rises by a factor of nine.

[D]'=3[D]

R'=9\times R

R'=k[D]'^x...[2]

[1] ÷ [2]

\frac{R}{R'}=\frac{k[D]^x}{k[D']^x}

\frac{R}{9R}=\frac{k[D]^x}{k[3D]^x}

9=3^x

Solving for x results in:

x = 2.

This indicates a second-order reaction.

The decomposition reaction's rate law is:

R=k[D]^2

The unit for the rate constant will be:

k=\frac{R}{[D]^2}=\frac{M/s}{(M)^2}=M^{-1}s^{-1}

The unit for the rate constant will be M^{-1}s^{-1}.

5 0
1 month ago
6.An acid-base indicator is usually a weak acid with a characteristic color in the protonated and deprotonated forms. Because br
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Answer:

When HBCG and BCG^- are at the same concentration, the resulting color is green. This green shade initially becomes visible at a pH of 3.8.

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HBCG serves as an indicator formed by dissolving solids in ethanol.

Since

Ka=[BCG−][H3O+][HBCG] When [BCG-] equals [HBCG], it follows that Ka = [H3O+].

<pWith a pH of 3.8,<pKa= [H3O+] = -antilog pH = -antilog (3.8)

Ka= 1.58 ×10^-4

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Which statement best describes the direction of heat flow by conduction between two samples of the same material?
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6 0
10 days ago
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How much CO2 (L) is produced when 2.10 kg of sodium bicarbonate reacts with excess hydrochloric acid at 25.0 °C and 1.23 atm? A)
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The equation representing the reaction between sodium bicarbonate and hydrochloric acid is as follows:

NaHCO_3_(_s_) + HCl_(_a_q_) \implies NaCl_(_a_q_) + CO_2_(_g_) + H_2O_(_l_)

The substances NaHCO_3 and HCl combine in a 1:1 ratio. Therefore, we calculate the quantity of sodium bicarbonate and its molar mass to determine the moles formed.

NaHCO_3_M_r = 22.99 + 1.008 + 12.011+ 3 \times 16.0= 84.01 g/mol.

2.1kg\ NaHCO_3 \times \frac{1000g}{kg} \times \frac{mol}{84.01g/mol} = 24.997\ mol.

We also recognize that the stoichiometric proportions are 1:1:1:1:1, which leads to the conclusion that the moles of CO_2 equal 24.977 moles.

Next, we apply the ideal gas equation PV=nRT, where P denotes pressure, V refers to volume, R is the gas constant, and T represents the temperature in kelvins. We rearrange to solve for V

PV= nRT \implies V= \frac{nRT}{P}= \frac{ 24.997\ mol \times 8.2507m^3\ atm \times 298.15K }{mol \times K \times 1.23 atm} = 49967\ m^3

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19 days ago
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Answer:

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By measuring the initial mass of each sample and the mass remaining after heating, the student can compute the oxygen gas mass released:

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Next, the moles of the original sample are determined:

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So, dividing the moles of oxygen released by 3 gives the moles of the sample.

Applying the formula molar mass = mass / moles, the student finds the molar masses of XClO₃ and ZClO₃.

Thus, this data allows answering question A: Which of X or Z has the higher molar mass?

5 0
1 month ago
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