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Roman55
1 month ago
11

A person is standing on a scale placed on the floor of an elevator. At time t1, the elevator is at rest and the reading on the s

cale is 500N. At a later time t2, the person is still standing on the scale and the reading on the scale is 400N . Based on the scale readings, which of the following statements about the motion of the elevator could be true at time t2?
a. The elevator is moving upward at constant speed.
b. The elevator is moving upward and slowing down.
c. The elevator is moving downward at constant speed.
d. The elevator is moving downward and slowing down.
e. The elevator is at rest.
Physics
2 answers:
Softa [3K]1 month ago
7 0
At time t2, it's plausible that the elevator is descending at a steady speed. Explanation: In this context, the elevator was stationary with a scale reading of 500N. At a later moment, when the reading drops to 400N, it indicates that the person is still on the scale. If an individual stands on a scale inside an accelerating upward elevator, their weight appears increased due to added pressure from the floor, resulting in a higher scale reading compared to when the elevator is motionless. Conversely, when the elevator descends, the sensation of lightness occurs. The force measured by the scale is termed apparent weight, which remains consistent at constant speeds. This can be analyzed through Newton's second law, which explains the forces at play when comparing rest conditions to motions.
serg [3.5K]1 month ago
7 0

Answer:

I would suggest that

Explanation:

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v = 4.08 m/s²

Clarification:

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If you are anchored in a fixed spot, and a set of six waves pass underneath you during a 60 second time interval, what is the wa
Ostrovityanka [3204]

Answer:

Explanation:

Within a duration of 60 seconds, six waves are observed.

With a total of 6 waves,

this equates to 3 wavelengths.

As a result,

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Thus, period = 20 seconds.

According to the frequency-period relationship,

f = 1 / T

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f = 0.05 Hz

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2 months ago
A student wants to determine the coefficient of static friction μ between a block of wood and an adjustable inclined plane. Of t
serg [3582]

Response:

A protractor to gauge the angle between the inclined plane and the horizontal

Explanation:

The student must elevate the free end of the adjustable inclined plane until the object just begins to slide and record the angle at that precise moment. At this juncture, the frictional force is balanced by the weight component aligned with the incline. That is:

f=\mu\,* N = \mu * m g\, cos(\theta)

and  w_{//}= m\,g\,sin(\theta)

Consequently, the coefficient of static friction can be entirely established by calculating the tangent of the angle formed by the incline with the horizontal.

f = w_{//}\\\mu *\,m \,g\,cos(\theta) = m\,g\,sin(\theta)\\\mu = tan(\theta)

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1 month ago
Which phrase describes an atom?
kicyunya [3294]
<span>an atom is described as having a negatively charged electron cloud surrounding a positively charged nucleus, which is the correct choice.</span><span>

The nucleus contains electrically neutral neutrons and positively charged protons, establishing its positive charge. In contrast, electrons carry a negative charge. The electromagnetic force keeps the atoms bound to the nucleus.
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2 months ago
Laser beam with wavelength 632.8 nm is aimed perpendicularly at opaque screen with two identical slits on it, positioned horizon
Softa [3030]

Response:

1 slit width = 0.158 mm, slit separation = 0.633 mm, distance between diffraction maxima = 12.7 mm

Explanation:

This involves defining several terms:

λ, the wavelength of the beam

D, the distance from the plane to the slit

x, the distance between minima in the diffraction pattern (in single slit setups)

w, the fringe width for double slit setups

1. In a double slit experiment, the fringe width is also recognized as the distance between Maxima.

Thus, w=λD/d, leading to d=λD/w when rearranged.

So, d= (632.8 x 10^-9 x 1 x 10^3)/1

which equals d= 0.633mm.

For single slit diffraction, minima are defined by a*sinΘ= m*x

where a is the slit width and m is an integer.

For small angles, it simplifies to Θ= (x/D) = (λ/a), allowing us to solve for a:

a = λD/a

a = (632.8x10^-9 x 1)/4

yielding a= 0.158mm.

2. A grating with 20 slits/mm gives d= 1/20mm= 0.05x10^-3.

To find y (the distance between maxima), apply y= λL/d:

Finally, y= (632.8 x 10^-9 x 1)/0.05x10^-3, which results in y= 12.7mm.

6 0
2 months ago
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