Response:
The new resistance is half of the original resistance.
Explanation:
Resistance in a wire is represented by:
= resistivity of the material
L and A are the physical dimensions
If a wire is exchanged for one where all linear dimensions are doubled, i.e. l' = 2l and r' = 2r
The updated resistance of the wire can be calculated as follows:
The new resistance equals half of the original resistance. Thus, this provides the solution needed.
Answer:
The energy delivered is E = 0.18 J
Explanation:
Given,
Battery voltage, V = 9 V
Charge in the circuit, Q = 20 mC
= 20 x 10³ C
Energy supplied in the circuit can be computed as
E = Q V
E = 20 x 10⁻³ x 9
E = 180 x 10⁻³
E equals 0.18 J.
The energy delivered in the circuit is therefore E = 0.18 J
The formula for the kinetic energy of any object in motion is
(1/2) (mass) (velocity²).
For the object you've mentioned, it translates to
(1/2) (100 kg) (12.5 m/s)²
= (50 kg) (156.25 m²/s²)
= 7,812.5 joules
______________________________
Beware that your attachment is heavily blurred and unreadable.
Response:
Clarification:
The force between two charges, q₁ and q₂ at a distance d is represented by the formula
F = k q₁ q₂ / d²
Here, the force between charge q₁ = -15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C with distance d = (1.66 - 1.24) = 0.42 mm
k = 1 / (4π x 8.85 x 10⁻¹²)
Substituting the values into the equation
F = 1 / (4π x 8.85 x 10⁻¹²) x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 9 x 10⁹ x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 35969.4 x 10⁻³ N.
For the force between charge q₂ = 34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C at a distance d = (1.24 - 0) = 1.24 mm.
Substituting the values into the expression
F = 1 / (4π x 8.85 x 10⁻¹²) x 34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 9 x 10⁹ x -34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 82729.6 x 10⁻³ N
Both forces direct towards the left (away from the origin, towards the negative x-axis)
Total force = 118699 x 10⁻³
= 118.7 N.
