No one is going to handle that for a mere 5 points lol.
Answer:
A rock weighing 50kg should be positioned at a distance of 0.5m from the pivot of the seesaw.
Explanation:
τchild=τrock
We will utilize the formula for torque:
(F)child(d)child)=(F)rock(d)rock)
The gravitational force acts equally on both objects.
(m)childg(d)child)=(m)rockg(d)rock)
We can eliminate gravity from both sides of the equation for simplification.
(m)child(d)child)=(m)rock(d)rock)
Now employing the given masses for the rock and child. The seesaw's total length is 2 meters, with the child sitting at one end, placing them 1 meter from the center of the seesaw.
(25kg)(1m)=(50kg)drock
Solve for the distance where the rock should be positioned in relation to the seesaw's center.
drock=25kg⋅m50kg
drock=0.5m
I do not concur with her stance. The concept of planetary motion emerges from a collaborative effort involving Johannes Kepler and Sir Isaac Newton. I believe Tycho Brahe's role was minimal since it was really Kepler who made the significant discoveries.
(this is my original response that was accepted)
The speed is V=27.24 m/s.
We need to utilize the linear momentum conservation principle:
The eagle's speed can be defined via two components:
Since speed is a scalar quantity.
a) Average power: 1425 W
b) Instantaneous power at 3.0 seconds: 2850 W
Given that the object moves along the ramp with uniform acceleration due to a constant force, we can apply the suvat equation:
s = 18 m (the distance covered along the ramp)
u = 0 (initial speed)
t = 3.0 s (time taken)
a is the acceleration of the object along the ramp
Calculating the acceleration 'a' using this data,
Next, we use Newton's second law to determine the net force acting on the object:
This net force consists of the applied force acting forward and the backward component of weight, allowing us to calculate the applied force.
m = 24 kg (mass of the object)
Now, we can compute the work done by the applied force, which runs parallel to the ramp:
s = 18 m (displacement)
The average power required is thus determined.
b) The instantaneous power at any point during the motion can be calculated using:
where F is the force applied and v is the object's velocity.
With the previously calculated applied force, as this is uniformly accelerated motion, we can also find the velocity at the end of the 3.0 seconds using the suvat equation:
