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FrozenT
13 days ago
12

5. Rubbing alcohol is a commonly used disinfectant and has a cooling effect when applied to the skin. The active ingredient in r

ubbing alcohol is isopropanol. In drugstores, the most common concentration of rubbing alcohol sold contains 70% (vol/vol) isopropanol in water. Assuming the rubbing alcohol manufacturer uses a 100% isopropanol solution, what volume of pure isopropanol is required to produce a 200-mL bottle of rubbing alcohol
Chemistry
1 answer:
VMariaS [2.6K]13 days ago
8 0

Answer:

The designation of 70% (vol/vol) indicates

that it contains 70% (vol/vol), meaning 70 ml of isopropanol is included in 100 ml of rubbing alcohol solution.

If it were 200 ml, then naturally, it would contain 70*2 = 140 ml of isopropanol required.

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What is the mass of a solution that has a density of 0.775 g/ml and a volume of 50.0ml?
Tems11 [2403]
Hello!

D = m / V

0.775 = m / 50.0

m = 0.775 * 50.0

m = 38.75 g
6 0
12 days ago
Three radioisotopes are being discussed in a chemistry class. Technetium-99m has a half-life of 6 hours. Rubidium-87 has a half-
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1 month ago
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A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o
Anarel [2605]

Response:

702 mL

To elaborate:

Given the following:

Mass of sodium hydroxide = 13.20 g

Molarity of H₂SO₄ = 0.235 M

We're tasked with finding the volume of acid necessary to neutralize the sodium hydroxide solution

Step 1: Write the balanced reaction equation

The reaction between H₂SO₄ and NaOH can be summarized as follows:

2NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + 2H₂O(l)

Step 2: Calculate the moles of NaOH

Moles are calculated by dividing mass by molar mass

The molar mass of NaOH is 40.0 g/mol

Hence;

Number of moles of NaOH = 13.20 g ÷ 40 g/mol

= 0.33 moles of NaOH

Step 3: Determine moles of H₂SO₄ that react

According to the balanced equation, 2 moles of NaOH react with 1 mole of H₂SO₄

Therefore, the ratio giving moles of H₂SO₄ = Moles of NaOH ÷ 2

= 0.33 moles ÷ 2

= 0.165 moles

Step 4: Find the volume of H₂SO₄

Molarity indicates the concentration of the solution in moles per liter

Molarity = Moles ÷ Volume

By rearranging the formula, we find volume = Moles ÷ Molarity

= 0.165 moles ÷ 0.235 M

= 0.702 L

= 702 mL

Thus, the volume of the 0.235 M H₂SO₄ acid solution required equals 702 mL
8 0
8 days ago
A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui
castortr0y [2743]

Answer:

The calculated density of the liquid is 1470.43 kg/m³.

Explanation:

Given:

Mass of the solid sphere (m) = 6.1 kg

Density of the metal = 2600 kg/m³

To find the volume of the liquid:

Volume(V)=\frac{Mass(m)}{Density (\rho)}

Volume of the sphere can be calculated as 6.1 kg / 2600 kg/m³ = 0.002346 m³.

According to Archimedes' principle, the volume of water displaced is equal to the volume of the sphere.

Volume displaced = 0.002346 m³

The buoyant force formula is:\rho\times gV

Where:

\rho is the fluid's density,

g represents the acceleration due to gravity,

V indicates the volume displaced.

Referencing the free-body diagram of the sphere shown in the image:

mg=\rho\times gV+T

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Using these in the equation to ascertain the liquid density yields:

6.1\times 9.81=\rho\times 9.81\times 0.002346+26

33.841=\rho\times 9.81\times 0.002346

\rho=\frac{33.841}{9.81\times 0.002346}

\rho=1470.43 kgm^3

Thus, the density of the liquid = 1470.43 kg/m³

6 0
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Eva buys a package of food, and the nutrition label says that
lorasvet [2542]

The answer is a total of 74,844 calories.

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