Yesinia read that certain perfume ingredients, called esters, would agitate bees. Because perfume formulas are secret, she decid
1 answer:
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Response:
0.8853 mL
Clarification:
Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:
- 13 lb *
= 5.902 kg
Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:
- 15 mg/kg * 5.902 kg = 88.53 mg
Finally, we compute the necessary mL of suspension, utilizing its concentration:
- 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
Answer:
Explanation:
Diethyl malonate possesses greater acidity compared to monocarbonyl substances (pKa=13) because its alpha hydrogens are linked to two carbonyl groups. Consequently, the malonic ester can be readily changed into its enolate ion by reacting it with sodium ethoxide in ethanol. When the malonic ester undergoes alkylation, a hydrogen atom in the alpha position becomes acidic, permitting another round of alkylation to yield a dialkylated malonic ester.
In this scenario, when diethyl malonate interacts with urea in the presence of sodium ethoxide base, the second alkylation step occurs within the molecule, producing a cyclic compound known as barbituric acid.
Answer:
180.56 kilojoules of heat energy is extracted when 1.00 kg of freon-11 evaporates.
Explanation:
The molar mass of freon-11 is 137.35 g/mol
The enthalpy of vaporization for freon-11 is 24.8 kJ/mol at its normal boiling point of 24°C. Given that,
The energy removed in the form of heat when 1.00 kg of freon-11 vaporizes is:
1) Drift velocity:
2. electrons per individual
Explanation:
1)
In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:
where
I stands for current
n represents the density of free electrons
indicates the charge of an electron
A signifies the wire's cross-sectional area
The wire's cross-sectional area can be determined as
where r denotes the wire's radius. Thus, the equation transforms to
In this scenario, we have:
I = 8.0 A as the current
indicates the free electron concentration
d = 1.5 mm is the diameter, making the radius
r = 1.5/2 = 0.75 mm =
So, the resulting drift velocity is:
2)
The entire length of the cord is
L = 3.00 m
And the cross-sectional area is
Consequently, the volume of the cord is
(1)
The number of electrons per unit volume is , thus the total electrons in this cord would be
Overall, the Earth's population rounds to 8 billion individuals, equating to
Hence, the number of electrons distributed to each person is: