Based on the equation:
ΔG = ΔH - TΔS = 0
It follows that ΔS = ΔH/T
So, ΔS = n*ΔHVap / Tvap
- where n represents the number of moles calculated as mass/molar mass
For a mass of 24.1 g
and a molar mass of 187.3764 g/mol
substituting gives:
∴ n = 24.1 / 187.3764g/mol
= 0.129 moles
The molar enthalpy of vaporization, ΔHvap, is 27.49 kJ/mol
The temperature in Kelvin, Tvap = 47.6 + 273 = 320.6 K
After substitution, we compute ΔS, the change in entropy:
∴ΔS = 0.129 mol * 27490 J/mol / 320.6 K
= 11 J/K
A triprotic acid is a type of Arrhenius acid that has the ability to donate three protons per molecule during dissociation in aqueous solutions. Thus, the chemical reaction, as outlined in the question, at the third equivalence point, can be expressed as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R denotes the counter ion of the triprotic acid. Consequently, the ratio of reacted acid to base at this point is 1:3.
The moles of NaOH are calculated as 0.106M*0.0352L = 0.003731 mole. Therefore, the amount of H3R is 0.003731mole/3=0.001244mole.
Subsequently, the molar mass of the acid can be determined: 0.307g/0.001244mole=247 g/mol.
The total number of moles of oxygen contained in the sample is 11.3 moles. Explanation: Based on the stoichiometry of the compound, 1 mole of
corresponds with 4 moles of CO or can be stated as 1 mole containing 1 mole of Ni, 4 moles of C, and 4 moles of O, leading to the conclusion that moles of C and O are equal. Therefore, since there are 11.3 moles of carbon present, there are likewise 11.3 moles of oxygen.
Answer:
Explanation:
The concept of mass balance around a distillation tower is utilized.
Each column undergoes mass and component balance, with relevant substitutions and analyses detailed in the attached documents.
