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ioda
1 month ago
7

Old Faithful geyser in Yellowstone National Park shoots water every hour to a height of 40.0 m. With what velocity does the wate

r leave the ground? (Disregard air resistance. g 9.81 m/s) a. 7.00 m/s c. 28.0 m/s d. 14.0 m/s b. 19.8 m/s 30.) A moderate force will break an egg. However, an egg dropped on the road usually breaks, while one dropped on the grass usually does not break because for the egg dropped on the grass, a. the b. the change in momentum is greater. time interval for stopping is greater. the change in momentum is less the time interval for stopping is less. . c. d.
Physics
2 answers:
Ostrovityanka [3.2K]1 month ago
5 0

Answer:

a) v \approx 28.010\,\frac{m}{s}, b)B. The time taken to stop is greater.

Explanation:

a)The initial velocity is determined through the Principle of Energy Conservation:

K = U_{g}

m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (40\,m)}

v \approx 28.010\,\frac{m}{s}

b)According to the Impact Theorem, the egg remains intact on the grass due to a significantly lower contact force and a longer stopping time. Thus, the correct answer is option B.

Keith_Richards [3.2K]1 month ago
5 0

Answer:

The answer is Option C = 28.0 m/s

Option B

Explanation:

Applying the conservation of energy principle, which accounts for the total energy of the system, including the sum of kinetic and potential energy. This principle considers the total energy in a system that changes through energy transfer in or out of that system.

From the problem,

the height of the water is h = 40m

and g = 9.81 m/s², the acceleration due to gravity

By summing the kinetic energy (energy of motion) and potential energy (energy based on position) = initial (Kinetic + potential) = final (Kinetic + potential)

(mgh + 1/2 mv²)initial = (mgh + 1/2 mv²)final

Disregarding the mass in both initial and final states,

V² = 2gh = 2 x 9.81 x 40 = 784.8 = 28.01 m/s

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Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, W, is linked to its specific mechanical power. Mechanical \ power calculated per unit mass can be derived from the following equation:

\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

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In a movie, Tarzan evades his captors by hiding under water for many minutes while breathing through a long, thin reed. Assume t
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1 month ago
For lunch you and your friends decide to stop at the nearest deli and have a sandwich made fresh for you with 0.300 kg of Italia
serg [3582]

Answer:

Part a)

A = 0.0581 m

Part b)

T = 0.37 s

Explanation:

A slice is dropped onto the plate from a height of 0.250 m,

therefore the speed of the slice upon impact is calculated as

v = \sqrt{2gh}

We know that

v = \sqrt{2(9.81)(0.250)}

v = 2.21 m/s

Now applying the conservation of momentum:

mv = (m + M)v_f

m = 0.300 kg

M = 0.400 kg

From this equation, we find:

0.300 (2.21) = (0.300 + 0.400) v_f

v_f = 0.95 m/s

0.400 (9.81) = 200 x_1

When the slice rests on the plate, the new mean position can be expressed as

x_1 = 0.01962 m

(0.300 + 0.400)9.81 = 200 x_2

We also determine that the speed of SHM is represented as

x_2 = 0.0343 m

Here, we derive values from

v = \omega\sqrt{A^2 - x^2}

\omega = \sqrt{\frac{k}{m + M}}

\omega = \sqrt{\frac{200}{0.300 + 0.400}}

\omega = 16.9 rad/s

a = x_2 - x_1 = 0.0343 - 0.01962 = 0.0147 m

Using the previous formula gives:

0.95 = 16.9\sqrt{A^2 - 0.0147^2}

A = 0.0581 m

Part b)

The time period for the scale is computed as

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{16.9}

T = 0.37 s

8 0
2 months ago
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