Answer:The pH measured 10 cm from the most acidic end is 3.42.
Explanation:
The pH at one end = 1The pH at the other end = 13
The chamber length = 13 cm
The change in pH concerning the chamber's length from the acidic end is
Thus, the pH at a distance of 10 cm from the most acidic end is 3.42.
Answer:
3.816 × 10⁻³ M
Explanation:
A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?
We can derive the following relations:
- The molar mass of Cu(NO₃)₂∙2.5H₂O is 232.59 g/mol.
- Each mole of Cu(NO₃)₂∙2.5H₂O yields one mole of Cu²⁺.
The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:

The molarity of Cu²⁺ is:

Answer:
The molar mass of the gas is 36.25 g/mol.
Explanation:
- To determine this, we utilize the mathematical relationship:
ν = 
Where, ν represents the speed of light in a gas (ν = 449 m/s),
R denotes the universal gas constant (R = 8.314 J/mol.K),
T stands for the temperature of the gas in Kelvin (T = 20 °C + 273 = 293 K),
M is the molar mass of the gas in (Kg/mol).
ν = 
(449 m/s) = √(3(8.314 J/mol.K)(293 K)/M,
by squaring both sides:
(449 m/s)² = (3(8.314 J/mol.K)(293 K))/M,
thus M = (3(8.314 J/mol.K)(293 K)/(449 m/s)² = 7308.006/201601 = 0.03625 Kg/mol.
Thus, the molar mass of the gas is 36.25 g/mol.
To find the answer, start by calculating the total mass of the copper utilized:
Copper used = 100 pennies x 3.0g Cu per penny = 300.0 g Cu
Next, identify the path and molar ratios from Cu produced back to CuFeS2 needed using the established balanced reactions:
1 Cu2S from 2 CuS; 2Cu from 1 Cu2S; 2CuS from 2CuFeS2
Thus, 2Cu comes from 2CuFeS2, indicating a 1:1 molar ratio.
Then convert grams of Cu to moles and grams of CuFeS2:
= 300.0 g Cu * 1 mol Cu/63.546g Cu * 2 mol CuFeS2/2 moles Cu
= 4.72 moles CuFeS2
The required amount of chalcopyrite mined = 4.72 moles CuFeS2 * 183.54 g CuFeS2/1 mole
CuFeS2 = 866.49 g CuFeS2