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Vikentia
11 days ago
14

You are instructed to deliver about 2 mL of water from a buret with a precision of 0.01 mL. Which of the following measured volu

mes is consistent with these instructions. a. 2.03 mL b. 1.87 mL C. 2.0 ml d.1.999 mL
Chemistry
1 answer:
KiRa [2.7K]11 days ago
7 0
The correct answer is C: 2.0 mL. This is due to the precision of the burette, which measures liquid volumes accurately with a precision of ±0.01 mL, indicating that it can reliably measure volumes around 2 mL without issue.
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You want to test the effect of pH on the distribution of Artemia in your 35cm long testing chamber. If you measure a pH = 1 at o
Tems11 [2403]

Answer:The pH measured 10 cm from the most acidic end is 3.42.

Explanation:

The pH at one end = 1The pH at the other end = 13

The chamber length = 13 cm

The change in pH concerning the chamber's length from the acidic end is

Thus, the pH at a distance of 10 cm from the most acidic end is 3.42.

x=\frac{13-1}{35 cm}=\frac{12}{35} pH/cm

7 0
17 days ago
A person loses 2.70 lbs in two weeks how many grams did he lose?
VMariaS [2693]
He lost 1224.7 grams.
6 0
1 month ago
Read 2 more answers
A stock solution of Cu2+(aq) was prepared by placing 0.8875 g of solid Cu(NO3)2∙2.5 H2O in a 100.0-mL volumetric flask and dilut
Anarel [2605]

Answer:

3.816 × 10⁻³ M

Explanation:

A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?

We can derive the following relations:

  • The molar mass of Cu(NO₃)₂∙2.5H₂O is 232.59 g/mol.
  • Each mole of Cu(NO₃)₂∙2.5H₂O yields one mole of Cu²⁺.

The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:

0.8875gCu(NO_{3})_{2}.2.5H_{2}O\times \frac{1molCu(NO_{3})_{2}.2.5H_{2}O}{232.59gCu(NO_{3})_{2}.2.5H_{2}O} \times \frac{1molCu^{2+} }{1molCu(NO_{3})_{2}.2.5H_{2}O} =3.816\times10^{-3} molCu^{2+}

The molarity of Cu²⁺ is:

\frac{3.816\times10^{-3} mol}{100.0 \times10^{-3}L} =3.816\times10^{-2}M

4 0
20 days ago
A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?
Tems11 [2403]

Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

  • To determine this, we utilize the mathematical relationship:

ν = \sqrt{3RT/M}

Where, ν represents the speed of light in a gas (ν = 449 m/s),

R denotes the universal gas constant (R = 8.314 J/mol.K),

T stands for the temperature of the gas in Kelvin (T = 20 °C + 273 = 293 K),

M is the molar mass of the gas in (Kg/mol).

ν = \sqrt{3RT/M}

(449 m/s) = √(3(8.314 J/mol.K)(293 K)/M,

by squaring both sides:

(449 m/s)² = (3(8.314 J/mol.K)(293 K))/M,

thus M = (3(8.314 J/mol.K)(293 K)/(449 m/s)² = 7308.006/201601 = 0.03625 Kg/mol.

Thus, the molar mass of the gas is 36.25 g/mol.


7 0
8 days ago
An average copper penny minted in the 1960s contained about 3.000 g of copper. how much chalcopyrite had be mined to produce 100
lorasvet [2542]

To find the answer, start by calculating the total mass of the copper utilized:

Copper used = 100 pennies x 3.0g Cu per penny = 300.0 g Cu



Next, identify the path and molar ratios from Cu produced back to CuFeS2 needed using the established balanced reactions:

1 Cu2S from 2 CuS; 2Cu from 1 Cu2S; 2CuS from 2CuFeS2
Thus, 2Cu comes from 2CuFeS2, indicating a 1:1 molar ratio.



Then convert grams of Cu to moles and grams of CuFeS2:
= 300.0 g Cu * 1 mol Cu/63.546g Cu * 2 mol CuFeS2/2 moles Cu

= 4.72 moles CuFeS2



The required amount of chalcopyrite mined = 4.72 moles CuFeS2 * 183.54 g CuFeS2/1 mole CuFeS2 = 866.49 g CuFeS2

8 0
22 days ago
Read 2 more answers
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