You are instructed to deliver about 2 mL of water from a buret with a precision of 0.01 mL. Which of the following measured volu

Answer:

The molality is 1.15 m.

Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.

Calculate moles of H₂SO₄ from molarity:

C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles

Mass of solvent (water) based on density:

m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg

Therefore, molality is:

m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m

Response:

9.1% deviation

Clarification:

Complete Question:

• The atomic radius of platinum was measured at 143 picometers. What is the corresponding percent error for this measured value?

The proportion of component A by mass for substance AB is given by 75%. Further explanation According to Proust's Comparative Law, compounds are made from elements that maintain the same Mass Comparison, ensuring that compounds have a consistent ratio of elements. The empirical formula presents the mole ratio of elements forming a compound. In the case of substance AB₂, 60.0% of its mass is attributed to A. For instance, if the mass of AB₂ is 100 grams, then the mass of A would be 60 grams, and the mass of B would be 40 grams, divided according to the coefficient in compound AB₂ which is 2, leading to 20 grams. Thus, for compound AB, the total mass is the sum of mass A and mass B, which equals 60 grams plus 20 grams, resulting in a total mass of 80 grams. Consequently, the percentage of compound A calculates to (60: 80) = 75%.

The connection between Gibb's free energy and temperature can be described as follows. The value for is specified as 1.7 kJ/mol. Additionally, we know that k =

= . Since k has a value of 0.50357 at a temperature of 298 K, we can conclude that

= 0.50357, leading to + 1 = 1.50357, which equals = 0.665. Therefore, we can deduce that 0.665 of the total fructose in the solution exists as fructopyranose.

Refer to the attached image. This does not depict the polymerization reaction of salicylic acid. It merely illustrates the structure of salicylic acid and what it looks like post-polymerization. The polymerization occurs through the linking of salicylic acid molecules, resulting in the formation of one water molecule.