Answer:

Explanation:
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In this scenario, as the molecular formula for the specified alcohol is C₄H₁₀O (with a molar mass of 74.14 g/mol), its combustion reaction can be represented as follows:

This implies a mole ratio of 1:4 with carbon dioxide (molar mass = 44.01 g/mol) and a mole ratio of 1:5 with water (molar mass = 18.02 g/mol), allowing us to determine the resultant masses as follows:

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Answer:
The correct statement is D. The water in Glass A is at a lower temperature compared to Glass B; consequently, the particles in Glass A exhibit reduced movement.
Explanation:
Raising the temperature increases the solubility of solutes.
The experiment indicates that's glass B is at a higher temperature than glass A since the antacid dissolves more quickly in glass B than in glass A. Therefore, glass A must be cooler, leading to slower particle movement compared to glass B.
Response:The ethanol percentage is 0.1093%
Explanation:
As given:
t = time = 10 s
I = current = 320 mA
F = Faraday's constant = 96485.3365 C mol⁻¹
n = number of electrons transferred = 4
Molecular weight of ethanol is 46 g/mol
Question: What is the percent (by volume) of ethanol in the driver's breath, %E =?
First, calculate the ethanol mass:

The moles of ethanol:

Applying the ideal gas law formula:

Here:
T = 26°C = 299 K
P = 1 atm
Substituting in the values:

The percentage of ethanol:
%
The density of human fat is
. The mass of the pure fat is 11.1 lbs.
First, convert the mass from pounds to grams as follows:
1 lb=453.592 g
Thus,

Density is defined as mass per unit volume, meaning volume can be calculated as:

By substituting the values,

Consequently, the volume gained by the individual will be
.
Answer:
The integer value of x in the hydrate is 10.
Explanation:

Molar concentration of the solution = 0.0366 M
Volume of the solution = 5.00 L
Moles of hydrated sodium carbonate = n


Weight of hydrated sodium carbonate = n = 52.2 g
Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol



By solving for x, we arrive at:
x = 9.95, approximating to 10
The integer x in the hydrate equals 10.