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Gennadij
13 days ago
8

By constructing basic electric circuits, you will be able to measure current flow. With Ohm’s law in mind, what broad question a

re you answering by doing this experiment?
Physics
2 answers:
Maru [1K]13 days ago
8 0

Answer:

A possible question is: How do variations in voltage or resistance influence the current flowing in an electrical circuit?

Explanation:

Ostrovityanka [942]13 days ago
5 0

Broad questions addressed by conducting this experiment involve the effects of electric current.

Additional details

Electric current measures the quantity of electric charge passing per unit time.

It results from electrons moving due to a voltage difference (high potential to low potential) between two points.

These electrons flow through wires acting as conductors.

Ohm's Law states that:

The potential difference across a conductor is proportional to the current flowing through it, assuming resistance remains the same.

\displaystyle I=\frac{V}{R}\\\\V=I\times R

A basic electrical circuit consists of a voltage source (battery) and a lamp.

Ammeters used to measure current must be connected in series with the load.

By adjusting the voltage while resistance is constant, varying current values are observed; increasing voltage produces higher current.

Learn more

Electron flow inside devices

brainly.com/question/4438943

Keywords: basic electric circuits, Ohm's law, experiment

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A spinning wheel is slowed down by a brake, giving it a constant angular acceleration of 25.60 rad/s2. During a 4.20-s time inte
Yuliya22 [1153]

We will use the equations of rotational kinematics,

\theta =\theta _{0} + \omega_{0} t+ \frac{1}{2}\alpha t^2             (A)

\omega^2= \omega^2_{0} +2\alpha\theta                                     (B)                                          

Here, \theta and \theta _{0} denote the final and initial angular displacements, respectively, whereas \omega and \omega_{0} represent final and initial angular velocities, and \alpha is the angular acceleration.

We are provided with \alpha = - 25.60 \ rad/s^2, \theta = 62.4 \ rad and t = 4.20 \ s.

By substituting these values into equation (A), we have

62.4 \ rad = 0 + \omega_{0} 4.20 \ s + \frac{1}{2} (- 25.60 \ rad/s^2) ( 4.20)^2 \\\\ \omega_{0} = \frac{220.5+ 62.4 }{4.20} =67.4 \ rad/s

Now, using equation (B),

\omega^2=(67.4 \ rad/s)^2 + 2 (- 25.60 \ rad/s^2)62.4 \ rad \\\\\ \omega = 36.7 \ rad/s

This indicates that the wheel's angular speed at the 4.20-second mark is 36.7 rad/s.

4 0
9 days ago
The maximum mass the can be hung vertically from a string without breaking the string is 10kg. A length of this string that is 2
serg [1198]

Respuesta:

Explicación:

Al analizar esta pregunta, considera el movimiento circular. Primero, determina la máxima fuerza que puede aplicarse al hilo. F = mg, entonces F = (10)(10) = 100 N. Luego, calcula la aceleración centrípeta de la masa de 0.5 kg, a = F/m, así que a = 100/.5 = 200 m/s². En la hoja de ecuaciones, usa la fórmula a (aceleración centrípeta) = v²/r, por lo que 200 = v²/2; por consiguiente, v = 20 m/s. ¡Espero que esto sea útil!

0 0
13 days ago
What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect?
kicyunya [1025]

<span>E = h x f </span>

<span>Thus: </span>

<span>f = E / h </span>
<span>f = 4.41•10^-19 / 6.62•10^-34 </span>
<span>f = 6.66•10^14 Hz (s^-1) </span>


<span>b/ What is the wavelength of this light? </span>
<span>------------------------------ </span>

<span>λ = c / f </span>
<span>λ = 3•10^8 / 6.66•10^14 </span>
<span>λ = 4.50•10^-7 m </span>
4 0
7 days ago
Read 2 more answers
When you apply the torque equation ∑τ = 0 to an object in equilibrium, the axis about which torques are calculated:
Softa [913]

Answer:

option D.

Explanation:

The correct choice is option D.

For an object in equilibrium, the torque measured at any point will be zero.

An object is deemed to be in equilibrium when the net moment acting on it equals zero.

If the object experiences a net moment not equal to zero, it will rotate and will not remain stable.

3 0
10 days ago
Part a consider another special case in which the inclined plane is vertical (θ=π/2). in this case, for what value of m1 would t
serg [1198]

The solution leads to the conclusion that m1 = m2

For mass m1, the force balance in the y direction equals zero:
0 = T - m1*g
Rearranging gives:
m1*g = T

For mass m2, the force balance in the y direction equals zero:
0 = T - m2*g
Rearranging provides:
m2*g = T

Setting these two equal allows us to solve for m1:
m1*g = m2*g

= m1 = m2

 

Explanation:

The force acting on each individual mass pulls down while the tension created by the other mass exerts an upward force due to the operation of the pulley system, resulting in balanced forces on both masses.

6 0
7 days ago
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